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Amanda [17]
2 years ago
13

I think it’s b but I’m not sure

Mathematics
1 answer:
laila [671]2 years ago
3 0
No, its D

Just look at the rounds mentioned and subtract the scores from higher round with lower round.

Look at A: round 2 score - round 1 score = -2?
-3 -1 = -4 change, not -2 change so it is wrong

Look at B: round 3 score - round 1 score =-1?
-2-1 =-3 change, not -1 change so it is wrong

Look at C: round 3 score - round 2 score =-1?
-2 -(-3) = 1 change, not -1 change so it is wrong

Look at D: round 3 score - round 1 score =-3?
-2-1 = -3 change, matches with -3 so it is correct.
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[(4096)⁰]⁻⁴ =<br> a)1/(4096)⁴<br> b)-4<br> c)4096<br> d)1
SOVA2 [1]

[(4096)⁰]⁻⁴ = (4096)⁰ = 1

OPTION D

5 0
3 years ago
Verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial
Mariulka [41]

Answer:

i) Since P(2), P(-1) and P(½) gives 0, then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

ii) - the sum of the zeros and the corresponding coefficients are the same

-the Sum of the products of roots where 2 are taken at the same time is same as the corresponding coefficient.

-the product of the zeros of the polynomial is same as the corresponding coefficient

Step-by-step explanation:

We are given the cubic polynomial;

p(x) = 2x³ - 3x² - 3x + 2

For us to verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial, we will plug them into the equation and they must give a value of zero.

Thus;

P(2) = 2(2)³ - 3(2)² - 3(2) + 2 = 16 - 12 - 6 + 2 = 0

P(-1) = 2(-1)³ - 3(-1)² - 3(-1) + 2 = -2 - 3 + 3 + 2 = 0

P(½) = 2(½)³ - 3(½)² - 3(½) + 2 = ¼ - ¾ - 3/2 + 2 = -½ + ½ = 0

Since, P(2), P(-1) and P(½) gives 0,then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

Now, let's verify the relationship between the zeros and the coefficients.

Let the zeros be as follows;

α = 2

β = -1

γ = ½

The coefficients are;

a = 2

b = -3

c = -3

d = 2

So, the relationships are;

α + β + γ = -b/a

αβ + βγ + γα = c/a

αβγ = -d/a

Thus,

First relationship α + β + γ = -b/a gives;

2 - 1 + ½ = -(-3/2)

1½ = 3/2

3/2 = 3/2

LHS = RHS; So, the sum of the zeros and the coefficients are the same

For the second relationship, αβ + βγ + γα = c/a it gives;

2(-1) + (-1)(½) + (½)(2) = -3/2

-2 - 1½ + 1 = -3/2

-1½ - 1½ = -3/2

-3/2 = - 3/2

LHS = RHS, so the Sum of the products of roots where 2 are taken at the same time is same as the coefficient

For the third relationship, αβγ = -d/a gives;

2 * -1 * ½ = -2/2

-1 = - 1

LHS = RHS, so the product of the zeros(roots) is same as the corresponding coefficient

7 0
3 years ago
Simplyfy 5 x a x 5 x a
prohojiy [21]

Step-by-step explanation:

5×a×5×a

collect like terms

5×5×a×a

25×a^2

25a^2

8 0
2 years ago
7. Two rectangles were used to form the following figure. The dimensions of both rectangles have been provided to the nearest ha
Irina-Kira [14]

Answer:

b

Step-by-step explanation:

edmentum

5 0
2 years ago
I don't know how do do it can u help me ​
Blizzard [7]

Answer:

The second regon

Step-by-step explanation:

4 0
2 years ago
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