The first thing we must do for this case is to define a variable.
We have then:
x: number of years before the Russo-Japanese conflict began
We write now the inequality that models the problem.
We know that the conflict began in the year 1904, therefore, all the previous years are given by:
x <1904
Answer:
an inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War is:
x <1904
RS is perpendicular to MN and PQ.
We can use the slopes of these lines to determine the answer.
Slope is given by the formula
m=.
Using the coordinates for M and N, we have:
m=.
Since PQ is parallel to MN, its slope will be as well, since parallel lines have the same slope.
Using the coordinates for points T and V in the slope formula, we have
m=.
This is not parallel to MN or PQ, since the slopes are not the same.
We can also say that it is not perpendicular to these lines; perpendicular lines have slopes that are negative reciprocals (they are opposite signs and are flipped). This is not true of TV either.
Using the coordinates for R and S in the slope formula, we have
m=. Comparing this to the slope of RS, it is flipped and the sign is opposite; they are negative reciprocals, so they are perpendicular.
Answer:
86m^2
Step-by-step explanation:
Answer:
No.
Step-by-step explanation:
Price of each pretzel = $3.25
Price of each drink = $1.85
Price of each bag of popcorn = $0.99
Maximum money to be spent = $10
Price of two pretzels = $3.25 
2 = $6.5
Price of two drink = $1.85 2 = $3.70
Price of two bags of popcorn = $0.99 2 = $1.98
Total money spent for buying two items of each type = $6.5 + $3.70 + $1.98 = $12.18
The money spent when 2 pretzels, 2 drinks and 2 bags of popcorn are bought is $12.18.
But maximum money available is $10.
Therefore, Clare would not be able to buy 2 pretzels, 2 drinks and 2 bags of popcorn with the amount of money available.
