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3 years ago

The

1 answer:

8 0

The median is nine (9). You add each number up, and then you divide by the amount of numbers you have.
The mean is 9.83 according to my calculations.

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Use the formula to evaluate the series 3+6+12+24+48+96

marysya [2.9K]

Multiplication by 2.

6 0

3 years ago

Read 2 more answers

A quadratic equation ax^2+bx+c=0 has -11 and 4 as solutions. Find the values of b and c if the value of a is 1 (hint, use zero f

Alina [70]

Answer:

b = 7, c = -44

Step-by-step explanation:

If the quadratic equation has the solutions -11 and 4, the two factors are:

$(x+11)(x-4)=0$

Since when we use the zero factor property we get

x+11=0 ⇒ x= -11

x-4=0 ⇒ x=4

Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.

Now we develop the multiplications between parenthesis:

$(x+11)(x-4)=0\\x^2-4x+11x-44=0\\x^2+7x-44=0$

So b is the number that accompanies the x: b = 7

and c is the independent number: c = -44

3 0

3 years ago

parents volunteer to make the cones they are given a recipe the recipe calls for 61/2 cups of flour duyi has already added 23/4

frozen [14]

6 1/2 - 2 3/4 = 3 3/4
6.5 - 2.75= 3.75

6 0

3 years ago

Help please need it by tonight

inysia [295]

Answer:

1) (n+5)(n-1)

2) (n-4)(n+3)

3) (v-4)(v-1)

4) (p-4)(p+2)

5)(7x-10)(x+1)

6)(7n-1)(n-9)

Step-by-step explanation:

1) Factors of -5 that add up to 4

2) Factors of --12 that add up to -1

3) Factors of 4 that add up to -5

4) Factors of -5 that add up to 4

5) 7 $x^{2}$ -3x-10

7 $x^{2}$ +7x-10x-10

7x(x+1)-10(x+1)

(7x-10)(x+1)

6)7 $n^{2}$ -64n+9

7 $n^{2}$ -63n-n+9

7n(n-9)-(n-9)

(7n-1)(n-9)

4 0

3 years ago

Find the product of (x – a) and (x - b).

yawa3891 [41]

(x−a)(x−b)

=(x+−a)(x+−b)

=(x)(x)+(x)(−b)+(−a)(x)+(−a)(−b)

=x2−bx−ax+ab

6 0

3 years ago