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3 years ago

Find the product. (v - 7su^2) (v + su^2) Enter the correct answer.

Mathematics

2 answers:

timurjin [86]3 years ago

5 0

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Reminder :

$(x + a)(x + b) = {x}^{2} + (a + b)x + (a \times b) \\$

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${v}^{2} + ( - 7s {u}^{2} + s {u}^{2})v +( ( - 7s {u}^{2})(s {u}^{2} )) = \\$

${v}^{2} - 6s {u}^{2} v - 7 {s}^{2} {u}^{4} \\$

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oksian1 [2.3K]3 years ago

4 0

Answer:

v² - 6su²v - 7s² $u^{4}$

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

= v(v + su²) - 7su²(v + su²) ← distribute both parenthesis

= v² + su²v - 7su²v - 7s² $u^{4}$ ← collect like terms

= v² - 6su²v - 7s² $u^{4}$

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In a basketball game, a regular basket is worth 2 points and a long distance basket is worth 3 points. There were 54 baskets in

Alla [95]

Answer:

The system of equations for the given situation is:

$x+y=54$

$2x+3y=118$

Step-by-step explanation:

Given:

Regular basket is worth = 2 points

Long distance basket is worth =3 points

Total baskets in a game = 54

Total points in total = 118

$x\rightarrow$ represents the number of regular baskets

$y\rightarrow$ represents the number of long distance baskets.

Expression for total baskets can be given by ⇒ $x+y$

Thus first equation representing total baskets in a game is given by:

$x+y=54$

Since a regular basket is worth 2 points

So $x$ regular baskets would be worth $=2x$ points

Since a long distance basket is worth 3 points

So $y$ long distance baskets would be worth $=3y$ points

Expression for total points in a game can be given by ⇒ $2x+3y$

Thus second equation representing total points in a game is given by:

$2x+3y=118$

∴ The system of equations for the given situation is:

$x+y=54$

$2x+3y=118$

3 0

3 years ago

A particular type of mouse's weights are normally distributed, with a mean of 359 grams and a standard deviation of 33 grams. If

igor_vitrenko [27]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Given:

$\mu = 359 \ \ \ \ \ \sigma = 33\\\\$

Using formula:

$\to P(X = x) = P\left ( z < \frac{x-\mu }{\sigma } \right )$

For point a:

$\to x= 406\\\\P(X < 406 ) = P\left ( z < \frac{406-359 }{33 } \right )\\\\$

$= P\left ( z$

For point b:

$\to x= 461\\\\P(X > 461 ) = P\left ( z > \frac{461 -359 }{33 } \right )\\\\$

$= 1 - P\left ( z < 3.0909 \right )\\\\= 1 - 0.9990\\\\= 0.0001$

For point c:

$\to x= 406\ \ and \ \ 461\\\\P(406$

$= 0.9990 - 0.9222\\\\= 0.0768\\\\$

For point d:

$P(X < 406) = 0.9222 = 92.22 \%\ that \ is \ greater \ than\ 50\%$

Hence, the correct choice is "i".

For point e:

$\to P(X > z) = 0.1\\\\\to 1 - P(X < z) = 0.1\\\\\to P(\frac{x-\mu }{\sigma }) = 0.9\\\\\to \frac{x-359}{33 } = 1.28\\\\ \to x = 401.24\\\\$

5 0

3 years ago

Which option or options is correct?

WITCHER [35]

All of them are true.

A: Rule.

B: There exist such functions f and g that satisfy the equality.

C: According to (A) this is acceptable.

D: Rule.

Hope this helps.

6 0

3 years ago

Solve the inequality -1/3h_<7

elixir [45]

Answer:

The solution to the given inequality

$h\geq \frac{-1}{21}$

Step-by-step explanation:

Given inequality

$\frac{-1}{3h} \leq 7$

⇒ -1≤ 7× 3h

⇒ -1 ≤ 21 h

⇒ 21 h ≥ -1

⇒ $h\geq \frac{-1}{21}$

5 0

3 years ago

Anyone wanna help please?

Varvara68 [4.7K]

Answer:

it's D.............................

3 0

4 years ago