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ExtremeBDS [4]
3 years ago
9

I need help finding the range and domain, you can use the images I've included for guidance! I need this asap thank youu

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

\displaystyle Range: \\ Set-Builder\:Notation → y|1 ≥ y ≥ -1 \\ Interval\:Notation → [-1, 1] \\ \\ Domain: \\ Set-Builder\:Notation → x|x ∈ R \\ Interval\:Notation → (-∞, ∞)

Step-by-step explanation:

This is the graph of \displaystyle y = cos\:x,in which its AMPLITUDE [<em>A</em>] ALWAYS starts ONE BLOCK ABOVE the <em>midline</em><em>.</em><em> </em>In the trigonometric formula below, −C gives the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle y = Acos[Bx - C] + D

NOTE: Depending on how your trigonometric graphs are structured, your vertical shift [<em>D</em>] might tell you to space out the amplitude of the graphs alot more evenly on both ends.

<u>Extended</u><u> </u><u>Information on</u><u> </u><u>Trigonometric</u><u> </u><u>Graphs</u>

\displaystyle Vertical\:Shift = D \\ Phase\:Shift\:[Horizontal\:Shift] = \frac{C}{B} \\ Period = \frac{2}{B}π \\ Amplitude = |A|

I am joyous to assist you anytime.

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WINSTONCH [101]

Answer:

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Wait for more responses if needed.

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2 years ago
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svetoff [14.1K]
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Brilliant_brown [7]

Answer:

by using Pythagoras theorm

{x}^{2}  +  {x}^{2}  =  {(9 \sqrt{2)} }^{2}  \\ 2 {x}^{2}  = 81 \times 2 \\ 2 {x}^{2}  = 162 \\  {x}^{2}  = 81 \\ x =  \sqrt{81}  \\ x = 9

Step-by-step explanation:

<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>
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dalvyx [7]

Answer:

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Step-by-step explanation:

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