6(10+z+3)
= (6)(10 + z +3)
= (6)(10) + (6)(x) + (6)(3)
= 60 + 6x + 18
= 6x + 78
Answer:
not sure tbh
Step-by-step explanation:
Answer:
45
Step-by-step explanation:
F(-4). F(x) = 2x^2 - x + 9
Answer:
$12
Step-by-step explanation:
assuming that the cost of delivery is constant irrespective of the number ordered
Let the cost of sandwich be x
First office
$33=4x+c where c is the cost of delivery
Second office
$61=8x+c
These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain
4x=28
Therefore, x=28/4=7
The cost of delivery is 33-(4*7)=33-28=5
Therefore, one sandwich plus delivery costs 7+5=$12
So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones

=

times

=

times

times

=

times 1 times 1=2/p
easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1
each member pays 2/p