V(r)=9*pi*r^2 what is the value of V(6)?
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Answer:
Step-by-step explanation:
Volume of a cone=1540, Radius=7cm.
The height of a cone=h
When we need to find the height of a cone, we can use the formula of the volume of a cone, which is to find the height of a cone.
Put the pi value=22/7 and the value of radius which is 7 cm into the formula.
Move to another side. 1540 divided by
to calculate what is the value of h, h is the height of a cone. Like this.
Rearrange the h.
I hope you will understand my solution and explanation. If you still cannot get the point, you can ask me anytime! Thank you!
If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB
Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°
Next, look at ΔADB. ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°
Now look at ΔADC. Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>
Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.
CD = 4 cm (given) so AC = 2(4 cm) = 8 cm
Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>
Lastly, look at ΔBHD. Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.
BD = 12 cm, so HD = = 6 cm
Answer: 6 cm