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Anvisha [2.4K]
3 years ago
10

Which word best describes the range of a function?

Mathematics
2 answers:
cluponka [151]3 years ago
7 0
The answer to the question is D
almond37 [142]3 years ago
3 0

Answer:

It is actually B output

Step-by-step explanation:

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1. 15 - (r +3 - 4) for r=3<br> @ 10<br> ® 7<br> 015
chubhunter [2.5K]

Answer:

3 add 1013 hay so youre welcome hoop

Step-by-step explanation:

just add it up

3 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
This is a practice test but I don’t understand stand this one pls help fast
Kisachek [45]

Step-by-step explanation:

To transform a function vertically, add 3 to the constant.

5 + 3 = 8

So the function is

3 {x}^{2}  + 8

Graph the function in desmos to show the translation vertically if you want proof

3 0
2 years ago
Find the coordinates of the midpoint of a segment with the given endpoints. *
serg [7]

Step-by-step explanation:

Given points are (-2,5) and (3,-17)

to find midpoint, use this formula

( x1+x2/2 , y1+y2/2)

where points are a(x1,y1) and b(x2,y2)

coming to the question,

midpoint is :

[ (-2-3)/2 , (5-17)/2 ]

[ -5/2 , -12/2 ]

[ -2.5 , -6 ]

OPTION A IS CORRECT

8 0
3 years ago
Read 2 more answers
2x+15=x/2-3<br><br> Can anyone solve for x?
____ [38]

Answer: X=-12

Right ain’t it ?

3 0
3 years ago
Read 2 more answers
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