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3 years ago

2x+15=x/2-3 Can anyone solve for x?

2 answers:

7 0

hello multiply everything by 2. this will cancel out the fraction. the equation will become 4x+30=x-6 then just combine like terms. subtract the x= 3x=-36 the answer is -12. x=-12

____ [38]3 years ago

3 0

Answer: X=-12

Right ain’t it ?

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What is 6/15 as a decimal

Tomtit [17]

6/15
equals 0.40

to calculate, 15 divided by 6 equals 0.40.

6 0

3 years ago

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A number p is less than 6 and greater than 2

DENIUS [597]

P can be a range of numbers from 3 to 5.

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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago

1. 5/2=-x/11<br><br> 2. 9/m=-4/11

alex41 [277]

Answer:

1. x = 55/2

2. x = - 99/4

5 0

3 years ago

A sample of students is taken from the school's A honor roll. The school estimates that there are actually 360 students on the A

Sergio [31]

Answer:

Number of 8th Graders = 360 - X

Step-by-step explanation:

As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from 8th grade.

As we know:

Total number of students on the A honor roll = 360

We are asked to calculate, number of students from 8th grade on the A honor roll.

So, let's assume that "X" represents the all the students who are on the A honor roll except 8th grade.

Mathematical Expression:

Number of 8th Graders = Total number of students on the A honor roll - X

Number of 8th Graders = 360 - X

So, if you know the value of X, you can easily calculate the number of students which are from 8th grade on the A honor roll.

3 0

3 years ago