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Nimfa-mama [501]
4 years ago
14

Use the diagram, which is not drawn to scale, to decide which proportions are true.

Mathematics
1 answer:
klemol [59]4 years ago
4 0

I think of these in terms of "short side", "long side" and "hypotenuse." The proportions will be true that equate the ratios of corresponding sides.

I is (long side of CDB)/(short side of CDB) = (long side of BDA)/(short side of BDA)

These are corresponding sides, so the proportion is <em>true</em>.

II is (hypotenuse of CBA)/(long side of CBA) = (long side of CBA)/(hypotenuse of CBA)

This proportion equates a value to its inverse, so is <em>false</em> (since the triangle has non-zero area)

III is (long side of CBA)/(short side of CBA) = (hypotenuse of CBD)/(long side of CBD)

The sides involved here are not corresponding, so this is <em>false</em>.

IV is (long side of CDB)/(hypotenuse of CDB)/(long side of BDA)/(hypotenuse of BDA)

These are corresponding sides, so the proportion is <em>true</em>.

The appropriate choice is ...

... a. I and IV only

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