Answer:
the third one is the correct answer
Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
A = 1/2 bh
A = 1/2 (21)(8)
A = 1/2 (168)
A = 84
8 can go into 12 only once.
You have to show the question more I can’t see the graph
