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blsea [12.9K]
4 years ago
13

70 POINTS!!URGENT!!!PLS HELP!!!!

Mathematics
1 answer:
sattari [20]4 years ago
8 0

You just need to find the y-values for the given x values.

1. f(-1)=0

2. f(2)=1

3. f(1)=1

4. f(-2)=-1

5. f(0)=1

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Jimmy has listed the amount of money in his wallet for each of the last ten days. He decides to remove day 7, as that was payday
abruzzese [7]

Answer:

The mean will reduce

Step-by-step explanation:

The total amount of money for the ten days divided by number of days will give mean 1, M₁

Removing the value for day seven will reduce the sum of money as it will be for 9 days only.In finding the mean, you will divide by 9 days to get mean M₂

Mean M₂ < M₁

8 0
3 years ago
Draw an angle of 40 degree. copy it's supplementary angle
Mila [183]
This is the correct form of a supplementary angle. 

3 0
3 years ago
What is the equation of a line that passes through the points (-3, 4) and (2,8)?
ziro4ka [17]

Given that the line passes through the two points (-3,4) and (2,8)

We need to determine the equation of the line.

<u>Slope:</u>

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (-3,4) and (2,8) in the above formula, we get;

m=\frac{8-4}{2+3}

m=\frac{4}{5}

Thus, the slope of the line is m=\frac{4}{5}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-3,4) and m=\frac{4}{5} in the above formula, we have;

y-4=\frac{4}{5}(x+3)

y-4=\frac{4}{5}x+\frac{12}{5}

     y=\frac{4}{5}x+\frac{12}{5}+4

     y=\frac{4}{5}x+\frac{32}{5}

Thus, the equation of the line is y=\frac{4}{5}x+\frac{32}{5}

6 0
3 years ago
3/8 \ 1/4= show your work ASAP
Rashid [163]
12/8=3/2 TIMES THE OPPOSITE <span />
8 0
4 years ago
Read 2 more answers
Find the volume of the wedge cut from the first octant by the cylinder z=12-3y^2 and the plane x+y=2.
LuckyWell [14K]

Answer:

The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2  

0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2  

V = ∫∫∫ dzdydx  

dz has changed from zero to 12−3y^2  

dy has changed from zero to 2-x  

dx has changed from zero to 2  

V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =  

24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20

Step-by-step explanation:

8 0
4 years ago
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