Step-by-step explanation:
the easiest way to answer this is to calculate the area of the large rectangle (white) and subtract the area of the small rectangular (black).
we know the dimensions of the small rectangle : 10×6
and because of the 2m thick "frame" we know the dimensions of the large rectangle by adding 2×2 m to every small dimension : 14×10
(2 m on the top and the bottom, and 2 m left and right, so 4 m added in every direction).
the area of the large rectangle is
14 m × 10 m = 140 m²
the area of the small rectangle is
10 m × 6 m = 60 m²
so the area of the path is
140 - 60 = 80 m²
Let Jeremy's age be x
if Jeremy's grandfather is four times as old as he is,grandfather's age is 4x
if the sum of their ages is 90, we have
x%2B4x=90
5x=90
x=90%2F5
x=18->Jeremy's age
Jeremy's grandfather will be 4x=4%2A18=72
answer:
D. 72
Answer: The average age is 7.1 years.
This problem is an example of when we need to take a weighted average. We simply can't just find the average of 5 and 8, because there are different children of each each.
To start, lets multiply the total number of children by their individual ages.
6 x 5 = 30 years
14 x 8 = 112 years
There are 142 years among the 20 years, so divide 142 by 20. This gives us an average age of 7.1 years.
From F.S 1, consider this series : 8, 1, 8, 8, 64, 64*8.
Again, consider the series 2, 1/4, 1/2, 1/8, 1/16, 1/(8*16). Clearly, the difference of the 6th and the 3rd term is different for them. Insufficient.
<span>From F.S 2, let the series be </span><span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span></span><span>. Now we know that </span><span><span>a<span>b2</span>=1</span><span>a<span>b2</span>=1</span></span>. The required difference =<span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span></span><span>= 0.Sufficient.</span>
Answer:
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