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Olenka [21]
3 years ago
5

At a certain bakery, the price of each doughnut is $1.50. Let the random variable D represent the number of doughnuts a typical

customer purchases each day. The expected value and variance of the probability distribution of D are 2.6 doughnuts and 3.6 (doughnuts)2 , respectively. Let the random variable P represent the price of the doughnuts that a typical customer purchases each day. Which of the following is the standard deviation, in dollars, of the probability distribution of P ? 1.5(3.6) 1.5(3.6) A 1.53.6−−−√ 1.53.6 B 1.5(3.6)−−−−−−√ 1.5(3.6) C 1.5(2.6) 1.5(2.6) D 1.52.6−−−√ 1.52.6 E
Mathematics
1 answer:
Solnce55 [7]3 years ago
6 0

Using <em>statistical concepts</em>, it is found that the standard deviation of the probability distribution is of

s = 1.5(1.9) = 2.85

When a constant is multiplied to each data in a variable, both the <u>mean and the standard deviation</u> are multiplied by the constant.

In this problem, the standard deviation, which is the square root of the variance, is of:

\sigma = \sqrt{\sigma^2} = \sqrt{3.6} = 1.9

The price of each is of $1.5, hence:

s = 1.5(1.9) = 2.85

A similar problem is given at brainly.com/question/25718546

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Colin used 836.55 gallons of water over the course of 6 days. To the nearest hundredth of a gallon, how much water did Colin use
Arturiano [62]

Answer:

139.43

Step-by-step explanation:

What I did was I divided 836.55 by 6 and came out to the answer: 139.425. Since you mentioned we needed to round up to the nearest hundredth, I rounded up the .425 to .43

8 0
3 years ago
Part 1 Write your own real-world scenario where the Pythagorean Theorem can be applied to find a missing piece. You may choose t
kondor19780726 [428]
I think this answers all the parts

Hope this helped :)

7 0
3 years ago
Admission to a baseball game is $4.00 for general admission and $5.50 for reserved seats. The receipts were $5973.50 for 1358 pa
MArishka [77]

Answer:

997 admission tickets were sold and 361 reserved seats were sold.

Step-by-step explanation:

There is a couple of ways to calculate this.

Multiply the cost of an admission ticket by the total paid admissions:

4 \times 1358 = 5432

Subtract this from the total cost:

5973.5 - 5432 = 541.5

Divide the above value by the difference between the cost of the two tickets:

5.5 - 4 = 1.5

541.5 \div 1.5 = 361

Now we know the number of general admission tickets, we can subtract the cost of this from the total cost:

361 \times 5.5 = 1985.5\\5973.50 - 1985.5 = 3988

Divide this by the cost of general admission:

3988 \div 4 = 997\\

So there were 997 admission tickets sold and 361 reserved seats sold.

Hope this helps!

3 0
3 years ago
A card is randomly selected from a standard
shepuryov [24]

Answer:

3 / 13

Step-by-step explanation:

Hello!

There are 52 cards in a deck with half being red and half being black. The question ask for when a black card is drawn so we divide the total by 2

52/ 2 = 26

There are 6 black face cards in a deck so to get the probability one will be drawn we put how many there are over the total amount

6/26 we can simplify this

3 / 13

The answer is 3 / 13

Hope this helps!

8 0
3 years ago
Read 2 more answers
Help me plz!!! Wanna know the answer of (d). Thank you so much!!!!
DIA [1.3K]

Answer:

d = -9

Step-by-step explanation:

First lets input our x value for g(x)

This gives us the integral

g(6) = \int\limits^6_{-4} {f(x)} \, dx

First, we need to split this integral into the different aspects of the piecewise function. This will give us

g(6)=\int\limits^0_{-4} {4} \, dx +\int\limits^5_0 {-5} \, dx +\int\limits^6_5 {0} \, dx

Now, we need to evaluate each of these integrals

\int\limits^0_{-4} {4} \, dx=4x|\limits^0_{-4}\\\\4(0)-4(-4)=16

\int\limits^5_0 {-5} \, dx=-5x|\limits^5_0\\\\-5(5)--5(0)\\\\-25

\int\limits^6_5 {0} \, dx=0

Now all we need to do is add the values of each of these integrals

16-25=-9

3 0
4 years ago
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