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3 years ago

The table below shows the preferences of 86 members of the National High Honor Society at Mosley High School.

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

Step-by-step explanation:

I got it right in the algebra nation

Hoochie [10]3 years ago

6 0

The correct answer is C) No, the percentage of students who prefer sports is higher than the percentage of students who prefer movies.

28/86 students prefer movies; 28/86 = 0.3256 = 32.56%
37/86 students prefer sports; 37/86 = 0.4302 = 43.02%

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Please help!! I have tried it on my own and I am stuck

elena55 [62]

Answer:

1. 23.59 feet

2. 32.9°

Step-by-step explanation:

1. See the diagram attached.

The man is 11 feet distance from the bottom of the tree.

And the angle of elevation from the man to the top of the tree is 65°.

Now, we need to approximate the height of the tree,

Using the trigonometry, we can write

$\tan 65^{\circ} = \frac{\textrm {Height of the Tree}}{\textrm {Base Distance}} = \frac{h}{11}$

⇒ h = 11 tan 65° = 23.59 feet (Approx.) (Answer)

2. See the diagram attached.

From the given right triangle the hypotenuse is 25 feet and the base is 21 feet.

And the angle between the hypotenuse and the base is the pitch of the ram of a NASCAR turn.

Using trigonometry, we can write

$\cos \theta = \frac{\textrm {Base}}{\textrm {Hypotenuse}} = \frac{21}{25}$

⇒ $\theta = \cos^{-1}(\frac{21}{25}) = 32.9^{\circ}$ (Answer)

8 0

3 years ago

6. A tank contains 100-gallon of pure water. At time t = 0, a solution containing 2 lb of salt per gallon flows into the tank at

SOVA2 [1]

Answer:

The answer is below

Step-by-step explanation:

Let Q represent the amount of salt in the tank at time t.

$\frac{dQ}{dt}= flow\ in - flow\ out\\ \\flow\ in=3\ gal/min*2\ lb/gal=6\ lb/min\\\\net\ gain\ in\ tank\ volume=3-4=-1, henceflow\ out= \frac{4Q}{100-t} \\\\\frac{dQ}{dt}= 6-\frac{4Q}{100-t} \\\\\frac{dQ}{dt}+ \frac{4Q}{100-t}=6\\\\The \ integrating\ factor\ is:\\\\IF=e^{\int\limits {\frac{4}{100-t} } \, dt }=e^{-4\int\limits {\frac{-1}{100-t}}=e^{-4ln(100-t)}=(100-t)^{-4}}\\\\Multiplying\ through \ by\ IF: \\\\(100-t)^{-4}\frac{dQ}{dt}+ (100-t)^{-4}\frac{4Q}{100-t}=6(100-t)^{-4}\\\\$

$Integrating:\\\\A(100-t)^{-4}=-2(100-t)^{-3}+c\\\\A=-2(100-t)+\frac{c}{(100-t)^{-4}} \\\\at, t=0,A=0\\\\0=-2(100-0)+\frac{c}{(100-0)^{-4}}\\\\c=0.02\\\\A=-2(100-t)+\frac{0.02}{(100-t)^{-4}}$

7 0

3 years ago

CAN SOMEONE PLEASE EXPLAIN HOW TO FIND THE AREA IN MATH!!!!! I’m in 8th grade

Airida [17]

Area is length times width.

Just some more info, volume is length times width times height.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Are these lines parallel

raketka [301]

Answer:

yes, they are parallel.

equation form is:

x=6

y=2

Step-by-step explanation:

7 0

3 years ago

Please help me, 6th grade math

Stells [14]

Answer:

Mean: 3.2 Median: 3.2 Mode:3.1 Range:0.5

Step-by-step explanation:

Easy.

5 0

3 years ago