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ipn [44]
2 years ago
10

What is the surface area of the triangular prism ?

Mathematics
2 answers:
jonny [76]2 years ago
4 0

Answer:

4320

Step-by-step explanation:

V=Bh

V=bbh/2

V=9*24*40

V=8640/2

V=4320ft

OLEGan [10]2 years ago
3 0

Answer:

2,376 square ft

Step-by-step explanation:

24*9*0.5*2=216(Area of two triangles)

40*15*2=1,200(Area of two rectangles on the sides)

24*40=960(Area of the third rectangle)

You add everything up, 960+1,200+216 and you get 2,376 square feet.

Hope this helps!~  :)

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Consider U = {x\x is a real number}
zysi [14]

Answer:

The fourth pair of statement is true.

9∈A, and 9∈B.

Step-by-step explanation:

Given that,

U={x|  x is real number}

A={x| x∈ U and x+2>10}

B={x| x∈ U and 2x>10}

  • 5 ∈ A , 5 ∈ B

If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.

Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.

So, 5∉A, and 5∉B.

  • 6 ∈ A , 6 ∈ B

If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.

Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.

So, 6∉A, and 6∈B.

  • 8 ∈ A , 8 ∈ B

If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.

Similarly, If 8∈ B, Then it will be satisfies 2x>10.  2.8=16>10.

So, 8∉A, and 8∈B.

  • 9 ∈ A , 9 ∈ B

If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.

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3 0
2 years ago
The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions
Mkey [24]

Answer:

Width = 18 inches

Length = 59 inches

Step-by-step explanation:

The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions

Perimeter of a rectangle = 2L + 2W

The length of a rectangle is five more than triple the width.

L = Length = 5 + 3W

W = Width

If the perimeter is 154 inches, what are the dimensions

Hence,

154 = 2L + 2W

154 = 2(5 + 3W ) + 2W

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Collect like terms

154 - 10 = 8W

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W = 144/8

W = 18 inches

Length = 5 + 3W

Length = 5 + 3(18)

Length = 5 + 54

Length = 59 inches

8 0
2 years ago
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