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2 years ago

Someone plzzz help I’m lost :(

Mathematics

1 answer:

JulsSmile [24]2 years ago

3 0

Answer:

j = (h-4) / k

Step-by-step explanation:

Unless there is more information given about this question somewhere else in the assignment, I'm assuming you are being asked to solve this equation for j.

If so, then its just a matter of rearranging the equation so that it is in the form

j = (expression containing other variables)

(h-4) / j = k (multiply both sides by j)

(h-4) = jk (divide both sides by k)

j = (h-4) / k

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Which of the following describes the scenario below?

Temka [501]

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3 years ago

What is the equation represented by the order pairs {(0,32),(1,16),(2,8),(3,4)}?

bagirrra123 [75]

Answer:

The equation represented by the ordered pair is;

y = 2^(5-x)

Step-by-step explanation:

Here, we want to write the equation represented by the ordered pairs

From what we have in the question, we can see that while the x-values increase in arithmetic progression of 1

The y-values decrease in order of two geometrically

Thus, the equation is;

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2 years ago

If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?

zepelin [54]

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2 years ago

Please Help Me! I will give all my point to who ever answers my question!!!

love history [14]

Step-by-step explanation:

The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

$V=2+\frac{1}{2} t$

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

$V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3$

$V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2} }{1} \\V_{avg}=\frac{1}{2}$

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when $t=1$ is 2.5 sec.

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2 years ago

What is 7.3 x 10 to the 2nd power

fredd [130]

7.3 * 10^2= 730. Just move the decimal two laces to the right.

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2 years ago

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