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Simora [160]
2 years ago
8

Can anyone help I'm I don't know what to do HELPP ME W/ MY HW PLEASEE

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
3 0
Fifi gets 1 cup.
And Honey's weight is 50 pounds.

Hope this helped!
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Your answer is going to be 4/9 :)

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Question 5<br> Solve for n.<br> HELP ASAP ILL GIVE U BRAINEST
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Answer:

The correct answer is – 4/7

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1. Complete the inequality below to describe the
dezoksy [38]

Domain is the entire span left to right (on the x-axis) that the graph is on. Since the graph goes from x=-4 and ends at x=4, the domain would be from -4 to 4. The circle at -4 is open, so it does not include the point at -4, just everything leading up to it. So, the domain would be

- 4 < x \leqslant 4

The range is similar, it is the entire span that the graph goes up and down (on the y-axis). The graph starts at the bottom at y=-2, and ends at y=5. The bottom point (4,-2) is closed, so the graph includes that point, and the top point (-4,5) is open and doesn't include the point. Therefore, the range would be

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2 years ago
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What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

in this problem we have

the point (5,12) is on the line of direct variation

so

Find the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

the equation is

y=\frac{12}{5}x

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

<u>case A)</u> point (0,0)

x=0\ y=0

Substitute the value of x and y in the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is true

therefore

the point (0,0) is on the line of direct variation

<u>case B)</u> point (2.5,6)

x=2.5\ y=6

Substitute the value of x and y in the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is true

therefore

the point (2.5,6) is on the line of direct variation

<u>case C)</u> point (3,10)

x=3\ y=10

Substitute the value of x and y in the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not  true

therefore

the point (3,10) is not on the line of direct variation

<u>case D)</u> point (7.5,18)

x=7.5\ y=18

Substitute the value of x and y in the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is true

therefore

the point (7.5,18) is on the line of direct variation

<u>case E)</u> point (12.5,24)

x=12.5\ y=24

Substitute the value of x and y in the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not true

therefore

the point  (12.5,24) is not on the line of direct variation

<u>case F)</u> point (15,36)

x=15\ y=36

Substitute the value of x and y in the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is true

therefore

the point (15,36) is on the line of direct variation

therefore

<u>the answer is</u>

(0,0)

(2.5,6)

(7.5,18)

(15,36)


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The sum of two number is 10. the difference between the numbers is 4. what are the two numbers.
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Your answer is 7 and 3.
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