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LuckyWell [14K]
3 years ago
11

What rule is used to estimate your total stopping distance under ideal conditions?

Chemistry
1 answer:
Nadya [2.5K]3 years ago
8 0
The 4 second rule is used to estimate your total stopping distance under ideal conditions.
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A ball has a mass of 2.0 kg and travels a distance of 24 meters in 10 seconds what is the Velocity
Amanda [17]
2.4 meters per second
8 0
3 years ago
What is the number of valence electrons in an atom of Al?<br> a. 13<br> b. 3<br> c. 10<br> d. 8
Svet_ta [14]
There are three valence electrons in an atom of Aluminum (Al).
                     ·
                   ·  ·
 ·              ·
Al ·  or    :    Al    :  ·
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The answer is B.
7 0
3 years ago
How many milliliters is 0.55 L?<br> O A. 1000 ml<br> OB. 0.00055 mL<br> O C. 550 ml<br> D. 55 mL
kolbaska11 [484]

Answer:

The Answer is C. 550 milliliters

3 0
4 years ago
A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58
Scilla [17]

Answer:

\% O=27.6\%

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}  =0.218molC

- Moles of hydrogen are contained in the 3.922 grams of water:

n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO

Finally, we compute the percent by mass of oxygen:

\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%

Regards.

5 0
4 years ago
Please help i really need it!
svp [43]

Answer:

mining away

Explanation:

8 0
3 years ago
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