Answer:
c is the answer then check it out
Answer:
0.162 moles of CO₂ are produced by this reaction
Explanation:
The reaction is:
C₃H₈(g) + 5O₂(g) → 3CO₂(g) +4H₂O(g)
As we have the volume of propane, we need to know the mass that has reacted, so we apply density's concept.
Density = Mass / Volume → Density . Volume = Mass
0.00183 g/mL . 1300 mL = Mass → 2.379 g
We determine the moles → 2.379 g . 1mol / 44 g = 0.054 moles
Ratio is 1:3. 1 mol of propane can produce 3 moles of dioxide
Then, 0.054 moles may produce (0.054 .3)/1 = 0.162 moles
All the answers are on the actual periodic table. You should never be told to remember it so I think this is a recourse you are allowed to look at whilst doing your homework lol :) all the answers are written on it hope it helps
Can you reword it im confused
Answer:
The answer to your question is: 4.5 %
Explanation:
0.126 moles of AgNO3
mass percent = ?
mass of water = 475 g
Formula
weight percent = weight of solute / weight of solution x 100
Weight of solute
MW AgNO3 = 108 + 14 + (16 x 3)
= 108 + 14 + 48
= 170 g
170 g of AgNO3 ------------------- 1 mol
x --------------------- 0.126 moles
x = (0.126 x 170) / 1 = 21.42 g of AgNO3
Weight percent = 21.42/475 x 100
= 4.5 %
