Answer:
Step-by-step explanation:
First you need to find the price for one binder. If 2 binders cost 4.36 you have to divide by 2 to find the price for 1. You should get 2.18. Then you have to see how many times you can multiply 2.18 without having the product go over 2.18. 2.18 • 22 = 47.96, the number closest to 50 without going over. Therefore, she can buy 22 binders.
Based on the given polynomial, the degree of the polynomial can be calculated to be 1.
<h3>what is the degree of the polynomial?</h3>
the degree of the polynomial is defined as the highest exponential degree or power in a polynomial.
from the above, we see that the highest power is 1 from 8x¹.
the degree of the polynomial is therefore 1.
find out more on the degree of the polynomial at brainly.com/question/2263735.
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Answer:
Step-by-step explanation:
Assume that the amount needed from the 5% acid is x and that the amount needed from the 6.5% acid is y.
We are given that:
The volume of the final solution is 200 ml
This means that:
x + y = 200
This can be rewritten as:
x = 200 - y .......> equation I
We are also given that:
The concentration of the final solution is 6%
This means that:
5%x + 6.5%y = 6% (x+y)
This can be rewritten as:
0.05 x + 0.065 y = 0.06 (x+y) ............> equation II
Substitute with equation I in equation II and solve for y as follows:
0.05 x + 0.065 y = 0.06 (x+y)
0.05 (200-y) + 0.065 y = 0.06 (200-y+y)
10 - 0.05 y + 0.065 y = 12
0.015y = 12-10 = 2
y = 2/0.015
y = 133.3334 ml
Substitute with the y in equation I to get the x as follows:
x = 200 - y
x = 200 - 133.3334
x = 66.6667 ml
Based on the above calculations:
The amount required from the 5% acid = x = 66.6667 ml
The amount required from the 6.5% acid = y = 133.3334 ml
Since the slope is (change in y)/(change in x), and a negative number over a positive number is negative (and vice versa), we want to figure that out. Therefore, we would want 2 to be bigger than the x value and 8 smaller than the y value, or the other way around. (0,9) fits the description, as well as (5, 6)
in the denominator is missing in the second expression. It should be
