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4 years ago

13

I need math help and I have the questions and images saved on a word document. To make it easier for myself does anyone know if

I can attach a file to this question?

1 answer:

Deffense [45]4 years ago

3 0

You can take a picture of the question with your phone or if the word document is in your phone you can screenshot it?

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Out of 400 applicants for a job, 179 are female and 72 are female and have a graduate degree. Step 2 of 2 : If 118 of the applic

Dafna11 [192]

Answer:

36/59 or 0.610

Step-by-step explanation:

P(female and degree)/P(degree)

72/118

36/59

0r 0.610

7 0

3 years ago

Solve then check solution

klio [65]

Answer:

1. z = 128

2. x = 4.2

3. c = 10

4. w = 100

5. a = 95.2

Step-by-step explanation:

1. Solve for z:

z/16 = 8

Multiply both sides of z/16 = 8 by 16:

(16 z)/16 = 16×8

(16 z)/16 = 16/16×z = z:

z = 16×8

16×8 = 128:

Answer: z = 128

_____________________________________________________

2. Solve for x:

3.5 x = 14.7

Divide both sides of 3.5 x = 14.7 by 3.5:

(3.5 x)/3.5 = 14.7/3.5

3.5/3.5 = 1:

x = 14.7/3.5

14.7/3.5 = 4.2:

Answer: x = 4.2

____________________________________________

3. Solve for c:

32 = 3.2 c

32 = 3.2 c is equivalent to 3.2 c = 32:

3.2 c = 32

Divide both sides of 3.2 c = 32 by 3.2:

(3.2 c)/3.2 = 32/3.2

3.2/3.2 = 1:

c = 32/3.2

32/3.2 = 10:

Answer: c = 10

__________________________________________________

4. Solve for w:

(2 w)/5 = 40

Multiply both sides of (2 w)/5 = 40 by 5/2:

(5×2 w)/(2×5) = 5/2×40

5/2×2/5 = (5×2)/(2×5):

(5×2)/(2×5) w = 5/2×40

5/2×40 = (5×40)/2:

(5×2 w)/(2×5) = (5×40)/2

(5×2 w)/(2×5) = (2×5)/(2×5)×w = w:

w = (5×40)/2

2 | 2 | 0

| 4 | 0

- | 4 |

| | 0

| - | 0

| | 0:

w = 5×20

5×20 = 100:

Answer: w = 100

___________________________________________________

5. Solve for a:

a/14 = 6.8

Multiply both sides of a/14 = 6.8 by 14:

(14 a)/14 = 14×6.8

(14 a)/14 = 14/14×a = a:

a = 14×6.8

14×6.8 = 95.2:

Answer: a = 95.2

6 0

3 years ago

Find the values of A B C AND D of <br> 4x^2 (2x^3+5x)= Ax^B +Cx^D

iren2701 [21]

The values are $A=8, B=5, C= 20$ and $D=3$

Explanation:

The expression is $4x^{2} (2x^{3} +5x)=Ax^{B} +Cx^{D}$

Simplifying, we get,

$8x^{5} +20x^3=Ax^{B} +Cx^{D}$

Since, both sides of the expression are equal, we can equate the corresponding values of A, B, C and D.

Thus, we get,

$8 x^{5}=A x^{B}$ ⇒ $A=8$ and $B=5$

Also, equating, $20 x^{3}=C x^{D}$ , we get,

$C=20$ and $D=3$

Thus, the values are $A=8, B=5, C= 20$ and $D=3$

3 0

3 years ago

What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?

victus00 [196]

Given the following information:

$\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] 
\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]
\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\
\end{tabular}$
$\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\
\end{tabular}$

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

$0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\ \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\ \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}$

Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

$0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\ \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\ \\ =0.00288+0.0056=\bold{0.00848}$

4 0

3 years ago

Please solve these! Read the instructions too!

sleet_krkn [62]

Just graph the coordinates
this picture is the different quadrants on the graph, whichever quadrant the coordinate is in, is what you put in the 2nd column
for example: (-2,-3) is in the 3rd quadrant
if its not in a quadrant its either on x or y axis, so its just on the line, and i assume you know which axis is which

for number 4. You just do subtraction, and then if its negative, it becomes positive since its asking for the absolute value
for example: |-24-11| > |-35| > 35

8 0

3 years ago