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Alexxandr [17]
3 years ago
6

Is 2/3 a solution of the equation?

Mathematics
2 answers:
balandron [24]3 years ago
6 0
No it isn't the solution to this equation is 2/1
Degger [83]3 years ago
6 0
No the answer is not 3/2

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A 99% confidence interval for the mean μ of a population is computed from a random sample and found to be 6 ± 3. We may conclude
valentina_108 [34]

Answer:

A. there is a 99% probability that μ is between 3 and 9.

Step-by-step explanation:

From a random sample, we build a confidence interval, with a confidence level of x%.

The interpretation is that we are x% sure that the interval contains the true mean of the population.

In this problem:

99% confidence interval.

6 ± 3.

So between 6-3 = 3 and 6 + 3 = 9.

So we are 99% sure that the true population mean is between 3 and 9.

So the correct answer is:

A. there is a 99% probability that μ is between 3 and 9.

4 0
3 years ago
Read 2 more answers
How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9
ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})

Where:

\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

\frac{5.9}{100}=0.059

Now we substitute the values:

PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})

Now we solve the operations, we get:

PV_{\text{ord}}=39462.50

Therefore, the present value must be $39462.50

8 0
1 year ago
College students average 8.6 hours of sleep per night with a standard deviation of 35 minutes. If the amount of sleep is normall
Soloha48 [4]

Answer:

4.27%

Step-by-step explanation:

We have been given that college students average 8.6 hours of sleep per night with a standard deviation of 35 minutes. We are asked to find the probability of college students that sleep for more than 9.6 hours.

We will use z-score formula to solve our given problem.

z=\frac{x-\mu}{\sigma}

z = z-score,

x = Random sample score,

\mu = Mean,

\sigma = Standard deviation.

Before substituting our given values in z-score formula, we need to convert 35 minutes to hours.

35\text{ min}=0.58\text{ Hour}

z=\frac{9.6-8.6}{0.58}

z=\frac{1}{0.58}

z=1.72

Now, we need to find P(z>1.72).

Using formula P(z>a)=1-P(z, we will get:

P(z>1.72)=1-P(z

Using normal distribution table, we will get:

P(z>1.72)=1-0.95728

P(z>1.72)=0.04272

0.04272\times 100\%=4.272\%

Therefore, 4.27% of college students sleep for more than 9.6 hours.

7 0
3 years ago
Simplify: 3/5x + x<br> Where 3 over 5 x plus x
hoa [83]
3/(5x) + x = 3/(5x) + x/1 * (5x)/(5x)
= 3/(5x) + 5x²/5x
= (3+5x²) / 5x
4 0
3 years ago
Read 2 more answers
Find the volume of this cone. <br><br> Round to the nearest tenth. <br><br> 10ft<br><br> 6ft
alexira [117]

Step-by-step explanation:

If radius = 6ft and height = 10 ft

volume of cone= (1/3)*pi*r^2*h

= (1*22*6*6*10)/3*7

(1*22*2*6*10)/7

3960/7

565.714

570ft

<h2><u>MARK ME AS BRAINLIST</u></h2>
3 0
1 year ago
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