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Alexxandr [17]
4 years ago
6

Is 2/3 a solution of the equation?

Mathematics
2 answers:
balandron [24]4 years ago
6 0
No it isn't the solution to this equation is 2/1
Degger [83]4 years ago
6 0
No the answer is not 3/2

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10 minus the product of 5 and a number g is more than 80.<br><br><br> How do you write that?
dangina [55]
It would be (5g) - 10 > 80
7 0
3 years ago
What is the sum of an infinite geometric series if a1 = 144 and r = 1⁄4?
Brilliant_brown [7]

Answer:

D

Step-by-step explanation:

The sum to infinity of a geometric sequence is

sum to infinity = \frac{a_{1} }{1-r}

here a_{1} = 144 and r = \frac{1}{4}, hence

sum = \frac{144}{1-\frac{1}{4} }

      = \frac{144}{\frac{3}{4} }

      = \frac{144(4)}{3} = 192 → D

7 0
3 years ago
1. A line segment has endpoints of Y(2,-3) and Z(-6,-1).
Orlov [11]

The answers will be :

a. The length of the line segment will be equal to 8.24 units.

b. The midpoint of the line segment will be ( -2 , -2 ).

c. The equation of line passing through points Y and Z will be 4y + x - 10 = 0

What is slope of a line segment ?

The ratio of the difference in y-coordinates over the equivalent x-coordinates between two different locations on a line.

It is given that a line segment has endpoints of Y(2,-3) and Z(-6,-1).

Let's solve the given parts based on the above data.

a.

The length of the line segment will be given by :

YZ = \sqrt({x_{2} - x_{1})^2 + (y_{2}- y_{1})^2}

YZ = √ [( -6 -(2)]^2 + [ -1 - (-3)]^2}

YZ = √ (-8)² + 2²)

YZ = √68

YZ = 8.24 units

b.

The midpoint (say M) of the line segment will be given by :

M = ( \frac{x_{1} + x_{2} }{2} , \frac{y_{1} + y_{2} }{2})

M = [(2-6)/2 , (-3-1)/2]

M = ( -2 , -2 )

c.

And the equation of line passing through points Y and Z will be :

y_{2} - y_{1} = m ( x_{2} - x_{1} )

Let's calculate value of slope (m) firstly which will be :

m =(y_{2} - y_{1}) / ( x_{2} - x_{1} )

m = ( -1 + 3 ) / (-6 - 2)

m = 2 / -8

m = -1 / 4

or

m = -0.25

Using the value of slope (m) : we get the equation of line as :

y - y_{1} = - 0.25 ( x - x_{1} )

or

(y + 3) = - 0.25 ( x - 2)

y + 3 = -0.25 x + 0.50

or

y + 0.25 x - 2.5 = 0

If we multiply by 4 throughout the equation ; then the equation of line can also be written as :

4y + x - 10 = 0

Therefore the answers will be :

a. The length of the line segment will be equal to 8.24 units.

b. The midpoint of the line segment will be ( -2 , -2 ).

c. The equation of line passing through points Y and Z will be 4y + x - 10 = 0

Learn more about line segment here ;

brainly.com/question/23629348

#SPJ1

5 0
1 year ago
Can somebody please help me with these two questions?
vovikov84 [41]
The answer to 25. is A
and 
to 26. is C (I'm not sure on this one but i think this is the answer)
6 0
3 years ago
Read 2 more answers
Find S15 for the geometric series 72 + 12 + 2 + +…
Sedbober [7]
S_{15}=72+12+\cdots+\dfrac1{181398528}+\dfrac1{1088391168}
S_{15}=72\left(\dfrac16\right)^0+72\left(\dfrac16\right)^1+\cdots+72\left(\dfrac16\right)^{13}+72\left(\dfrac16\right)^{14}
S_{15}=72\displaystyle\sum_{i=1}^{15}\left(\frac16\right)^{i-1}

\dfrac16S_{15}=72\displaystyle\sum_{i=1}^{15}\left(\frac16\right)^i

\implies S_{15}-\dfrac16S_{15}=72\displaystyle\sum_{i=1}^{15}\bigg(\left(\dfrac16\right)^{i-1}-\left(\dfrac16\right)^i\bigg)
\dfrac56S_{15}=72\bigg(\left(1-\dfrac16\right)+\left(\dfrac16-\dfrac1{6^2}\right)+\cdots+\left(\dfrac1{6^{13}}-\dfrac1{6^{14}}\right)+\left(\dfrac1{6^{14}}-\dfrac1{6^{15}}\right)\bigg)
\dfrac56S_{15}=72\left(1-\dfrac1{6^{15}}\right)
S_{15}=\dfrac{432}5\times\dfrac{6^{15}-1}{6^{15}}=86.4
6 0
3 years ago
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