3 years ago

Is 2/3 a solution of the equation?

2 answers:

6 0

No it isn't the solution to this equation is 2/1

6 0

No the answer is not 3/2

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MArishka [77]

If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
y = 6/2 = 3

Therefore, m<TSU = 4(3) + 11 = 12 + 11 = 23

7 0

3 years ago

lutik1710 [3]

Answer:

The distance formula is $d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)2}$

The midpoint formula is $\left(\frac{x_1\:+x_2}{2}\right),\left(\frac{y_1-y_2}{2}\right)$

Step-by-step explanation:

apply the pythagorean theorem on a coordinate grid

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3 years ago

Aliun [14]

It’s base * height so 28

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3 years ago

kaheart [24]

I think the answer would be

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3 years ago

Blababa [14]

Answer:

Step-by-step explanation:

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3 years ago