Answer:
The answer is "Option c".
Explanation:
In the given question the device A is connected by 3 wires, contributing all of them, which also includes several connector paths. When all the wires of A are broken down, and if all of this leaves no routes that can be used. Even so, if it is done to E, it's also linked to four different routes. Its solution would've been C because its value will be the MINIMUM.
Answer:
The answer to the given question can be given as:
The value of *iptr is 7. and the value of iptr is dynamic.
Explanation:
In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.
Answer:
void main(){
string name;
printf("Enter Name\n");
stdin("%s",&name);
Printf("\nGreetings %s",name);
}
Explanation:
Here scanf is represented by stdin and we are using that scanner object to read the string value from user.The value which we read are printed in a new line using printf .The format specifier %s in printf is replaced by name variable
Answer:
D
Explanation:
the answer is D because it does exactly what the problem says.
