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cricket20 [7]
2 years ago
7

PLEASE HELP!!!!! (Environmental Science Semester 1)

Computers and Technology
2 answers:
uranmaximum [27]2 years ago
6 0
I believe the answer would be B, Sorry if I'm wrong! ❤
kiruha [24]2 years ago
3 0

the answer is B. When used properly, science can answer any questions....(angles singing *XD*)

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Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
Select the correct answer. Cerise is explaining computer viruses to her students. What is the best way for her to explain a comp
Anna [14]

Answer:

B. it is a code that creates multiple copies on loading and damages the system

Explanation:

it is a app which they send to you on your computer or mobile phone

maybe click this link you will get free gift

3 0
3 years ago
Renee just got on the freeway to go to her cousin's house in Denver. She is driving 50 miles per hour. Her sister Kim left one h
defon

let's say they catch-up to each other after t hour.

so

in t hour distance travelled by Renee

d = speed × time = 50t

in t hour distance travelled by Kim

d = speed × time = 60(t-1) + 0×1 = 60(t-1)

Note: here kim didn't covered any distance in first hour and in rest t-1 hour it travelled all distance

now.as distance travelled by both is same so

60(t-1) = 50t

60t -60 = 50t

adding 60 both sides

60t = 50t+60

subtracting 50t both sides

60t -50t = 50t+60 - 50t

10t = 60

dividing by 10 both sides

t = 60/10 = 6

so in 6 hour both will catch-up to each other

3 0
3 years ago
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac
Vikentia [17]

Answer:

input-year taken 2020

2020 is divisible by 2

output- 2020 is a leap year

3 0
3 years ago
Write a program that prompt the user to enter the coordinate of two points (x1, y1) and (x2,y2), and displays the slope of the l
zzz [600]

Answer:

Here is code in C++.

//include headers

#include <bits/stdc++.h>

using namespace std;

//main function

int main() {

//variables to store coordinates

float x1,x2,y1,y2;

cout<<"Please Enter the coordinate of first point (x1,y1): ";

// reading coordinate of first point

cin>>x1>>y1;

cout<<"Please Enter the coordinate of second point (x2,y2): ";

// reading coordinate of second point

cin>>x2>>y2;

//calculating Slope of the line that connects these points

float m=(x2-x1)/(y2-y1);

cout<<"Slope of the line that connects these two points is :  "<<m<<endl;

}

Explanation:

Declare four variables x1,x2,y1,y2 to store the coordinate of both points.

Read the coordinate of both the point from user. Calculate the slop of the

line which connects these two points with the formula m=(x2-x1)/(y2-y1).

Output:

Please Enter the coordinate of first point (x1,y1): 1 3                                                                                                        

Please Enter the coordinate of second point (x2,y2): 5 12                                                                                                      

Slope of the line that connects these two points is :  0.444444  

3 0
3 years ago
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