Answer:
see explaination
Explanation:
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
double temp1,temp2,inc,cel;
int i=1;
while(i==1)
{
i=0;
cin>>temp1>>temp2>>inc;
if(temp2<temp1||inc<=0)
{
i=1;
cout<<"Starting temperature must be <= ending temperature and increment must be >0.0\n";
}
}
cout<<endl;
cout<<setw(15)<<"Fahrenheit"<<setw(15)<<"Celsius";
while(temp1<=temp2)
{
cel=(temp1-32)/1.8;
cout<<endl;
cout<<fixed<<setprecision(3)<<setw(15)<<temp1<<setw(15)<<cel;
temp1+=inc;
}
}
Please kindly check attachment for output.
Answer:
No, because it would be generally free for private-sector employees by using filtering software to restrict access to some websites.
Explanation:
Maria working for the following Corporation, a major private-owned company that specializes throughout ball bearings production. That corporation establishes filtering software to restrict access to some of these sites linked to non-work, and also some sites with poπnographic images.
So, Maria could not challenge that policy lawfully, as private-sector employees are usually free to always use filtering software to restrict access to some of these Websites
Answer:
ELECTRONICS
a range of frequencies within a given band, in particular that used for transmitting a signal.
2.
the energy or mental capacity required to deal with a situation.
Explanation:
Answer:
-
= 1
= 1
Explanation:
Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.
To determine the quantum numbers you must do the electron configuration.
Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.
The rank of energy is:
1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d
You must fill the orbitals in order until you have 18 electrons:
- 1s² 2s² 2p⁶ 3s² 3p⁶ : 2 + 2 + 6 + 2 + 6 = 18 electrons.
The last electron is in the 3p orbital.
The quantum numbers associated with the 3p orbitals are:
- = 1 (orbitals s correspond to = 0, orbitals p correspond to = 1, orbitals d, correspond to = 2 , and orbitals f correspond to = 3)
- can be -1, 0, or 1 (from - to + )
- the fourth quantum number, the spin can be +1/2 or -1/2
Thus, the six possibilities for the last six electrons are:
- (3, 1, -1 +1/2)
- (3, 1, -1, -1/2)
- (3, 1, 0, +1/2)
- (3, 1, 0, -1/2)
- (3, 1, 1, +1/2)
- (3, 1, 1, -1/2)
Hence, the correct choice is:
- = 1
- = 1
