A. They can only be separate chemically
Answer:
result=0;
for (i=lo ; i<=hi; i++){
result += i;
}
Explanation:
The question says result was declared but not initialized, so using result without initializing it to 0 would throw an error as result would be undefined and you can't add a number to undefined
Another way to do it to keep everything inside the loop would be
for (i=lo ; i<=hi; i++){
if (i==lo) result= 0;
result += i;
}
but this is impractical since it would add unnecesary operations in each cycle of the loop
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
<span>A return statement causes a value to be sent from a called method back to the calling method.
</span>When used in computer programming the return statement causes execution to leave the current subroutine and resume at the return address, where the term return address denotes the point <span>in the code immediately after where the subroutine was called.</span>
