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2 years ago

How many pairs of potential clients can be randomly chosen from the pool of eight candidates?

Mathematics

2 answers:

Lelechka [254]2 years ago

6 0

It would be 28 pairs

sweet [91]2 years ago

4 0

1 12 13 14 15 16 17 18
2 23 24 25 26 27 28
3 34 35 36 37 38
4 45 46 47 48
5 56 57 58
6 67 68
7 78
8
approximately 28 pairs. (breakdown above) hope this helps

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The distance from a point to a line is the length of the ____________ segment from the point to the line.

solniwko [45]

Answer: 1) Perpendicular

2) Concurrent

Step-by-step explanation:

The distance from a point to a line is the length of the perpendicular segment from the point to the line.

As Perpendicular segment is the shortest distance to the point of the line.

When three or more lines intersect at one point, they are concurrent.

Because Concurrent is a situation when three or more lines intersect each other at a single point.

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Eight kids got to go to the water park for $60. How many students could go for $195? Explain how you know.

Naddika [18.5K]

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2 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

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2 years ago

Find the area of the following shape

blsea [12.9K]

Answer:

56.8 m²

Step-by-step explanation:

This shape is clearly a trapezium / trapezoid. So :

Area of a trapezium is given by the formula :

$\frac{a+b}{2} h$

Substitute values given in diagram :

a = 4.2

b = 10

h = 8

$(\frac{4.2+10}{2} )8$

7.1 × 8 = 56.8

Units will be m² as this is area

Giving us our final answer of 56.8 m²

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1 year ago