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Sonbull [250]
3 years ago
15

How many pairs of potential clients can be randomly chosen from the pool of eight candidates?

Mathematics
2 answers:
Lelechka [254]3 years ago
6 0
It would be 28 pairs

sweet [91]3 years ago
4 0
1 12 13 14 15 16 17 18
2 23 24 25 26 27 28
3 34 35 36 37 38
4 45 46 47 48
5 56 57 58
6 67 68
7 78
8
approximately 28 pairs. (breakdown above) hope this helps

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Please help!!! <br> And try to show your work if you can:)
maxonik [38]

Answer:

equation~ 2x + 5= 2X + 8

Value of X~ 0.3

Perimeter:13

Step-by-step explanation:

equation: 2x + 5 =2x +8

 2x + 5= 2x+ 8              

 4x + 5= 8

   4X= 13

x= 0.3

value of X: 0.3

Perimeter: 13

8 0
3 years ago
Help does anybody no this I've been sick on this question for hours?? Number 18.
ANTONII [103]
You just have to divide the bigger x value by the smaller x value
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4 years ago
if you roll a 12-sided die - numbered 1-12 - what is the probability of rolling a number divisible by 4?
Natali [406]
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8 0
3 years ago
Read 2 more answers
Suppose that x and y are positive integers such that x^2 * y^3=46656. What is the sum of all possible values of x?
Nostrana [21]

Answer:

252

Step-by-step explanation:

  • x² * y³=46656

<u>Prime factors of 46656:</u>

  • 46656 = 2⁶3⁶

<u>Possible values of x:</u>

  • (2*3)³= 216
  • 3³ = 27
  • 2³ = 8
  • 1

<u>Sum of them:</u>

  • 216 + 27 + 8 + 1 = 252
3 0
3 years ago
I need help with this question
Molodets [167]

Answer:

wow pretty hard

Step-by-step explanation:

4 0
4 years ago
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