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2 years ago

How many pairs of potential clients can be randomly chosen from the pool of eight candidates?

Mathematics

2 answers:

Lelechka [254]2 years ago

6 0

It would be 28 pairs

sweet [91]2 years ago

4 0

1 12 13 14 15 16 17 18
2 23 24 25 26 27 28
3 34 35 36 37 38
4 45 46 47 48
5 56 57 58
6 67 68
7 78
8
approximately 28 pairs. (breakdown above) hope this helps

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Find the solutions of the system y = –2x – 1 and y = 3–x–1.

sweet [91]

There are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.

<h3>What is an exponential function?</h3>

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent y = a^x

where a is a constant and a>1

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two equations:

y = –2x – 1 and

$\rm y = 3^{-x-1}$

From the graph, we can see:

There are two intersection points:

(-1, 1) and (-2, 3)

The x coordinates are -1 and -2

x = -1, y = 1

x = -2, y = 3

Thus, there are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.

Learn more about the exponential function here:

brainly.com/question/11487261

#SPJ1

5 0

2 years ago

Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

8 0

2 years ago

Water pours into a tank at the rate of 2000 cm3/min. The tank is cylindrical with radius 2 meters. How fast is the height of wat

Gennadij [26K]

Volume of water in the tank:

$V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h$

Differentiate both sides with respect to time t :

$\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}$

V changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for dh/dt :

$2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}$

$\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}$

(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)

7 0

3 years ago

Kimberly traveled 28 miles.She traveled twice as many miles as Joe but one third as many miles as Brina .How many miles did Joe

marishachu [46]

Kimberly-28
2x Kimberly( Joe)-28/2=14
Brina-I don’t know:((
It’s either 28/‘33=9.33
Or 28*.33=84.

7 0

3 years ago

I need helpppp?!!! What is the slope of the line?? Please give right answer

galben [10]

Answer: -1/2

Step-by-step explanation:

Slope=rise/run

Up 1 and to the left 2 which makes it a negative

6 0

3 years ago

Read 2 more answers