<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
Answer:
negatively charged
Step-by-step explanation:
Answer:
So buddy this is going to get a bad rating I know but I'm going to help you out as much as I can without seeing a picture so for linear equations the formula is y=mx+b anyways the slope is m and to find it, look at the line and see how many times it goes up till it lands on a correct point. once you have that you can see how many times it went up and over. Because your slope is your rise over run (rise/run) and so for example <em>if</em> it was c then it would be 3/3 meaning it goes up 3 and over 3. So to find the right one just find a starting point and see how much it goes over to the right. if it goes over to the left then its negative instead of run over to the right. And if it goes down instead of rise then its negative. Hope this helps you find your answer now and in the future.
Vsphere=(4/3)pir³
d/2=r
given
d=4
d/2=r=4/2=2
Vsphere=(4/3)pi2³
Vsphere=(4/3)pi8
Vsphere=32/3pi
using pi=3.14
Vsphere=33.493333333333 cm³
round
Vsphere=33 cm³
Phase angle (∅) in a parallel RL circuit is given by the formula; tan∅ 
where 
is current through the inductor and given by 
and 
is current through the resistor and given by 
hence, tan∅ 
or ∅ = 26.565 degree
