P1=(0,0)=(x1,y1)→x1=0, y1=0
P2=(3,-2)=(x2,y2)→x2=3, y2=-2
Slope: m=(y2-y1)/(x2-x1)
m=(-2-0)/(3-0)
m=(-2)/3
m=-2/3
Point-slope equation:
y-y1=m(x-x1)
y-0=(-2/3)(x-0)
y=-(2/3)x
Answer: The equation of the line is: y=-(2/3)x
By the binomial theorem,
where
Then the coefficients of the 
terms in the expansion are, in order from 
to 
,
Answer:
Look below
Step-by-step explanation:
Ok, you got a Quadrilateral with the side lengths 6, 9, 9, 12
The shortest of B is 2
Find the scale factor of the A to B
6 -> 2
6/2 = 3
Scale factor is 3
Now divide all the sides by scale factor
6/3, 9/3, 9/3, 12/3 = 2, 3, 3, 4
Add them all together to get the perimeter
2+3+3+4 = 12
Perimeter of B is 12
Answer:
Step-by-step explanation:
50
+
2
Answer:
Jada should have multiplied both sides of the equation by 108.
Step-by-step explanation:
The question is incomplete. Find the complete question in the comment section.
Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:
Step 1: Multiply both sides of the equation by -9/4 as shown:
-4/9 × -9/4 = x/108 × -9/4
-36/-36 = -9x/432
1 = -9x/432
1 = -x/48
Cross multiplying
48 = -x
x = -48
It can also be solved like this:
Given -4/9 = x/108
Multiply both sides by 108 to have:
-4/9 * 108 = x/108 * 108
-4/9 * 108 = 108x/108
-432/9 = x
x = -48
Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.
