Answer this question correctly and get a FREE BRAINLY AND POINTS (Difficulty: Algebra?) ...

Mathematics

2 answers:

Zepler [3.9K]3 years ago

8 0

Answer:

-14400

Step-by-step explanation:

6/2 (-75*4³)=-14400

4³=64

6/2(-75*64)

6/2(-4800)

3(-4800)=-14400

Serggg [28]3 years ago

8 0

- 114400 by multiplying the 6/2 by the numbers in the parentheses

You might be interested in

Hhhhhhheeeeelllllpppppppp

professor190 [17]

Answer:

tan 41 = 0.87

sin 63 = 0.89

cos 14 = 0.97

Step-by-step explanation:

No explanation since the question states to use the ALEKS calculator so you just make sure the calculator is in degrees then simply press tan 41 etc.

8 0

3 years ago

Your task is to build a road joining a ranch to a highway that enables drivers to reach the city in the shortest time. The perpe

lubasha [3.4K]

Answer:

(a)In the attachment

(b)The road of length 35.79 km should be built such that it joins the highway at 19.52km from the perpendicular point P.

Step-by-step explanation:

(a)In the attachment

(b)The distance that enables the driver to reach the city in the shortest time is denoted by the Straight Line RM (from the Ranch to Point M)

First, let us determine length of line RM.

Using Pythagoras theorem

$|RM|^{2}=30^2+x^2\\|RM|=\sqrt{30^2+x^2}$

The Speed limit on the Road is 60 km/h and 110 km/h on the highway.

Time Taken = Distance/Time

Time taken on the road $=\frac{\sqrt{30^2+x^2}}{60}$

Time taken on the highway $=\frac{50-x}{110}$

Total time taken to travel, T $=\frac{\sqrt{30^2+x^2}}{60}+\frac{50-x}{110}$

Minimum time taken occurs when the derivative of T equals 0.

$T^{'}=\frac{x}{60\sqrt{30^2+x^2}}-\frac{1}{110}\\\frac{x}{60\sqrt{30^2+x^2}}-\frac{1}{110}=0\\\frac{x}{60\sqrt{30^2+x^2}}=\frac{1}{110}\\110x=60\sqrt{30^2+x^2}\\$

Square both sides

$12100x^2=3600(30^2+x^2)\\12100x^2=3240000+3600x^2\\12100x^2-3600x^2=3240000\\8500x^2=3240000\\x^2=\frac{3240000}{8500} =381.18\\x=\sqrt{381.18} =19.52$