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Pavel [41]
3 years ago
15

When you use the ip address of the web server, the correct site is displayed?

Computers and Technology
1 answer:
jekas [21]3 years ago
6 0
No. Using the address will get you either the default site, or the first site declared. Web servers can host VirtualHosts, and rely on the site name to know which VirtualHost to serve. TMI, it's called name based virtual host, as opposed to the machine having many addresses then address based virtual hosts can be created.
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0.0% complete question a forensics analyst is attempting a live acquisition of the contents of the memory of a running linux dev
Sonja [21]

Based on the question, the  Recommendation of  a framework that will enable the analyst to install a kernel driver is said to be Volatility.

<h3>What is the Volatility framework?</h3>

Volatility is said to be a kind of an open source framework that is known to be used in times of memory forensics as well as digital investigations.

Note that The framework is one that tends to inspects and take out the memory artifacts that pertains to 32-bit and 64-bit systems. The framework has aided for all kinds of Linux, Windows, and others.

Hence, Based on the question, the  Recommendation of  a framework that will enable the analyst to install a kernel driver is said to be Volatility.

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8 0
2 years ago
A company has implemented the capability to send all log files to a central location by utilizing an encrypted channel. The log
klemol [59]

Answer:

Install recommended updates.

Explanation:

To resolve this exploit the company has to install recommended updates. Since their encryption is prone or unsecured so to have better encryption or more secured encryption they have to install recommended updates.Since log files getting transferred over this channel so the company would not want to someone mess with their log files.

3 0
3 years ago
Consider sending a 2400-byte datagram into a link that has an mtu of 700 bytes. suppose the original datagram is stamped with th
Feliz [49]

Explanation:

Let, DG is the datagram so, DG= 2400.

Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.

Let, M is the MTU so, M=700.

Let, IP is the IP header so, IP= 20.

Let, id is the identification number so, id=422

Required numbers of the fragment = [\frac{DG-IP}{M-IP} ]

Insert values in the formula = [\frac{2400-20}{700-20} ]

Then,        = [\frac{2380}{680} ] = [3.5]

The generated numbers of the fragment is 4

  • If FV = 1 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=0 and F=1.
  • If FV = 2 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=85(85*8=680 bytes) and F=1.
  • If FV = 3 then, bytes in data field of DG= 720-20 = 680 and id=422 and FO=170(170*8=1360 bytes) and F=1.
  • If FV = 4 then, bytes in data field of DG= 2380-3(680) = 340 and id=422 and FO=255(255*8=2040 bytes) and F=0.

3 0
4 years ago
What does UAS stand for
dezoksy [38]

Answer: Unmanned Aircraft Systems

Explanation:

8 0
3 years ago
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