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Serjik [45]
3 years ago
7

Distance between Train 1 and Train 2 = 95 miles. Average speed of Train 1 = 45 mph. Average speed of Train 2 = 60 mph. Train 1 i

s ahead of Train 2 on the same track. How long before Train 2 would overtake Train 1 if neither train is re-routed?
Mathematics
2 answers:
Norma-Jean [14]3 years ago
7 0
X=vt
v=60-45=15
95=15*t
t=95/15=6 1/3
Art [367]3 years ago
3 0

Answer: Its C

Step-by-step explanation: Train 2 is traveling 4 miles per hour faster than train

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xxTIMURxx [149]

Let p be the prize of a pen and m the prize of a mechanical pencils. If you buy six pens and one mechanical pencil, you spend 6p+m. We know that this equals 9, because you get 1$ change from a 10$ bill.

Similarly, if you buy four pens and two mechanical pencils, you spend 4p+2m, which is 8$, because now you get a $2 change. Put these equation together in a system:

\begin{cases} 6p+m=9\\4p+2m=8\end{cases}

Now, if you multiply the first equation by 2, the system becomes

\begin{cases} 12p+2m=18\\4p+2m=8\end{cases}

Subtract the second equation from the first:

12p+2m - (4p+2m) = 18-8 \iff 8p = 10 \iff p = \dfrac{10}{8} = 1.25

Plug this value into the first equation to get

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Read 2 more answers
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
1 year ago
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