Answer:
The given equation is
⇒y≥
As domain of the function is 3 x-2≠0
x≠2/3
⇒For different values of x we get different values of y.
When, x>2/3 , we get positive values of y.
So , y≥ 0
and when x< 2/3 , we get values of y which are negative.
i.e y≤0
At x=2/3, function is not defined.So at that point there does not exist any value of y.
The equation of a line is written in form y = Mx+ b
M is the slope, also known as the gradient.
You are given the gradient and one point , which is an x and y value. Using that solve for b:
1. Gradient = 2, x = 4, y= 3
3 = 2(4) + b
3 = 8 + b
Subtract 8 from both sides:
B = -5
The equation becomes y = 2x-5
2. Gradient = -3, x= -1, y = 7
7 = -3(-1) + b
7 = 3 + b
Subtract 3 from both sides:
B = 4
Equation becomes: y = -3 +4
Answer: 7
Step-by-step explanation: The only pattern in this sequence that I can see is addition by 4. Therefore, the 3rd term is 15, the 2nd is 11, the 1st is 7.
Please consider Brainliest.
Find the marginal density for 
by integrating the joint PDF over all possible values of 
:
Then the density of 
conditioned on is
for 
and undefined elsewhere.
Thus
= = =
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