Answer:
492.6g
Explanation:
Given parameters:
Number of moles of MgSO₄.7H₂O = 2moles
Unknown:
Mass = ?
Solution:
To find the mass of this compound;
Mass = number of moles x molar mass
Molar mass of MgSO₄.7H₂O = 24.3 + 32 + 4(16) + 7[2(1) + 16]
= 246.3g/mol
Mass = 2 x 246.3 = 492.6g
Answer:
The mole is represented by Avogadro's number, which is 6.022×1023 atoms or molecules per mol
Explanation:
<span>The alkali metals and hydrogen are reactive because they have only one electron to give in order to complete their valence shell. It is easier to give that one electron so when given the opportunity they will. This means they will react with anything polar or willing to take an electron.</span>
Nitrogen followed by oxygen
Answer:
6.28
Explanation:
Let's consider the following reaction at equilibrium.
CH₄(g) + H₂O(g) ⇌ 3 H₂(g) + CO(g)
The concentration equilibrium constant (Kc) is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.
Kc = [H₂]³ × [CO] / [CH₄] × [H₂O]
Kc = 1.15³ × 0.126 / 0.126 × 0.242
Kc = 6.28
