Answer:
Most of free energy available from oxidation of the glucose remains in pyruvate.
Explanation:
The overall reaction of the process glycolysis is:
Glucose + 2 NAD⁺ + 2 ADP + 2 Pi ⇒ 2 Pyruvate + 2 NADH + 2 H⁺ + 2ATP
Glucose is oxidized to give 2 molecules of pyruvate and 2 molecules of NADH and ATP (Energy currency).
<u>Though the free energy of oxidation of glucose is high but only 2 NADH is formed because the most of the free energy that is being released from the oxidation of glucose remains in the pyruvate which is produced in the reaction and thus only 2 molecules are formed.</u>
Answer:
Na = 32.4% , % S = 22.6% and %O = 45.0%
Explanation:
% Na = 3.4/10.5. × 100%
= 32.4%
%S = 2.37/10.5 × 100%
= 22.6%
% O= 4.73/10.5 × 100%
= 45.0%xplanation:
Answer:
Since valence shells are mostly empty in nonmetal atoms, the atoms attract and hold any electrons they can in order to fill their valence shells.
1 mol of CO2 is 44.01g/mol
So multiply that by 2 to get 2 mol of CO2, which is 88.02g
There are a total of four quantum numbers that govern the
electrons. These are the principal quantum number (n), the angular quantum
number (l), the magnetic quantum number (ml) and lastly the spin quantum number
(ms). Each electron has a unit set of the four quantum numbers.
Since the first 3 quantum numbers is already specified, so
the remaining to be filled is the ms quantum number which can only have values
of +1/2 and -1/2. So we have 2 electrons.
Answer:
<span>2 electrons</span>
