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3 years ago

8

Arcturus is a star whose surface temperature is 4290 K. What is most likely the color of Arcturus? What is most likely the mass

of Arcturus? about solar masses

2 answers:

Snowcat [4.5K]3 years ago

8 0

Answer:

orange

0.8

Explanation:

On egde

sasho [114]3 years ago

7 0

Answer: orange and 0.8

Explanation: edge2021

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Luba_88 [7]

The answer is D. easier, higher

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3 years ago

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List five examples of matter and five examples that are not matter. Explain your answer.

ASHA 777 [7]

Answer:

An apple,a person.a table,a computer,wood because they occupies space

non matter=Light, heat, kinetic and potential energy, and sound are non-matter because they are massless

3 0

3 years ago

Which change would cause an immediate increase in the rate of the forward reaction

Studentka2010 [4]

According to Le Chatelier's Principle, to increase the rate of the forward reaction we add more of the reactants to encourage more collisions and production of more products. If it is endothermic, more heat should be added. If it is endothermic, more heat should be released from the system.

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3 years ago

PLEASE HELP ASAP ONLY HAVE 10 MINUTES. A certain photon of light has a wavelength of 422 x 10 -9 m. What is the frequency of the

Sedaia [141]

Answer:

7.11 x $10^{14}$ Hz

Explanation:

The equation for converting wavelength to frequency is ν=c/λ, or the speed of light over wavelength. The speed of light is 3.00 x $10^{8}$ , and our wavelength here is 422 x $10^{-9}$ . All we have to do now is substitute our given values:

$\frac{3.00x10^{8} }{422x10^{-9}}$

After reduction, our answer comes out to be about 7.11 x $10^{14}$ Hz.

4 0

3 years ago

A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

Ede4ka [16]

<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

4 0

3 years ago