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Ne4ueva [31]
3 years ago
9

Olive oil is a cooking Ingredient. The density of olive oil is 0.92 grams per cubic centimeter. An olive farmer wants to sell bo

ttles that contain
460 grams of oil. What is the volume of the smallest container that holds 460 grams of oll?​
Mathematics
1 answer:
sveticcg [70]3 years ago
7 0

Answer: The volume of container that holds 460 grams of oil is 500 cm³.

Step-by-step explanation:

Density of olive oil is 0.92 grams/(centimetre )^3

An olive farmer wants to sell bottles that contain  460 grams of oil.

Therefore

Mass of oil  = 460 grams

As we know

\text {Density}= \dfrac{\text{Mass}}{\text{Volume}} \\\\\Rightarrow 0.92= \dfrac{460}{\text{Volume}} \\\\\Rightarrow \text{Volume}= \dfrac{460}{0.92} = 500

Hence, the volume of container that holds 460 grams of oil is 500 cm³.

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What expression is equivalent to 13-(-21)?
Naddik [55]

Answer:

34

Step-by-step explanation:

13-(-21) = 13 + 21 = 34

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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista
mrs_skeptik [129]

Answer:

Step-by-step explanation:

R=5

T=4.5

D=22.5

5x4.5=22.5

Maybe this is right ? Hope it helps

3 0
3 years ago
What is a distributive property of 72 divided by 4
djverab [1.8K]

Answer:

\frac{72}{4}=18

Step-by-step explanation:

To find : What is a distributive property of 72 divided by 4 ?

Solution :

The distributive property of division is given by,

\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}

We have to divide 72 by 4,

So, Re-write 72 as 60+12.

Substitute,

\frac{72}{4}=\frac{60+12}{4}

\frac{72}{4}=\frac{60}{4}+\frac{12}{4}

\frac{72}{4}=15+3

\frac{72}{4}=18

Therefore, \frac{72}{4}=18

7 0
3 years ago
A football player scores 40 goals in 60 games find the rate of scoring goals per game
valentinak56 [21]

Answer:

0.7 (rounded)

Step-by-step explanation:

Step-by-step explanation:

40 goals/60 games

40/60 = 0.7 (rounded)

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A boat on the ocean is 2 mi from the nearest point on a straight? shoreline; that point is 15 mi from a restaurant on the shore.
Sladkaya [172]

Answer:

a) x  =  0,70 miles

T  =  1/2* (√4 + x²)  +( 15 - x )/3   Objective Function to minimize

b) V(min)  = 2.59 m/hr

Step-by-step explanation:

Let assume the boat is in Point A,  she lands in point B, and R  is the restaurant

Let call  x distance between the point O in  which perpendicular line from the boat get to shoreline, and the point were she land.

We know  distance is

d = v*t       ⇒  t = d/v

She rows at 2 miles/hr  and walk at 3 miles /hr

According to that she takes

c (hypotenuse) of right triangle  AOB/ 2 rowing

and  15 - x /3  walking

Total time is:

T  =  c/2  + ( 15-x )/3          c =√(2)² + x²     ⇒  T = [√(2)² + x²  ] /2  +  ( 15-x )/3  

T  =  1/2* (√4 + x²)  +( 15 - x )/3   (1)

And that is  the Objective function to minimize

a) Taking derivatives on both sides of the equation we get

T´(t)  =  x /( √4 + x²)  - 1/3    ⇒   T´(t)  = 0     x /( √4 + x²)  - 1/3 = 0

3*x - √( √4 + x²) = 0     ⇒  3*x  =  √( √4 + x²)

Squaring both sides

9x²  =  4 + x²     ⇒  8x²  = 4       x² = 1/2      x  =  0,70 miles

If we plug this value in the Objective function we will get the minimum time

1/2* (√4 + x²)  +( 15 - x )/3    ⇒ [√ 4  + 0,5] /2 +  14,3/3 = T (min)

T(min)  =  1.06 + 4.77  = 5.83 hr

Distance L (hypotenuse of right triangle AOR)

L = √(2)²  + (15)²   L  = 15,13 miles

And that distance have to be traveled at least in 5.83 hr rowing

Then  as  v = d/t      V(min)  =  15.13/ 5.83   ⇒    V(min)  = 2.59 m/hr

6 0
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