Answer:
Age of q = 42 years
Step-by-step explanation:
Ratio of the ages of three people p, q and r is 6 : 7 : 11
Sum of the ages of p and r = 102 years
Age of p = ![\frac{6}{(6+11)}\times (102)](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%286%2B11%29%7D%5Ctimes%20%28102%29)
= 36 years
Therefore, age of r = 102 - 36
= 66 years
Since, ratio of p and q = 6 : 7
Therefore, ![\frac{\text{Age of p}}{\text{Age of q}}=\frac{6}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BAge%20of%20p%7D%7D%7B%5Ctext%7BAge%20of%20q%7D%7D%3D%5Cfrac%7B6%7D%7B7%7D)
![\frac{36}{q}=\frac{6}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B36%7D%7Bq%7D%3D%5Cfrac%7B6%7D%7B7%7D)
q = ![\frac{36\times 7}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B36%5Ctimes%207%7D%7B6%7D)
q = 42 years
After solving the expression
the value of y is ![y=\frac{5}{9}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5%7D%7B9%7D)
Step-by-step explanation:
We need to solve the expression
to find value of y
Solving:
![\frac{3y-2}{3}+\frac{2y+3}{3}=\frac{y+7}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B3y-2%7D%7B3%7D%2B%5Cfrac%7B2y%2B3%7D%7B3%7D%3D%5Cfrac%7By%2B7%7D%7B6%7D)
Taking LCM of 3,3 and 6 is 6
Multiply all terms by 6
![\frac{3y-2}{3}*6+\frac{2y+3}{3}*6=\frac{y+7}{6}*6\\(3y-2)*2+(2y+3)*2=y+7](https://tex.z-dn.net/?f=%5Cfrac%7B3y-2%7D%7B3%7D%2A6%2B%5Cfrac%7B2y%2B3%7D%7B3%7D%2A6%3D%5Cfrac%7By%2B7%7D%7B6%7D%2A6%5C%5C%283y-2%29%2A2%2B%282y%2B3%29%2A2%3Dy%2B7)
Simplifying:
![6y-4+4y+6=y+7\\](https://tex.z-dn.net/?f=6y-4%2B4y%2B6%3Dy%2B7%5C%5C)
Combining like terms:
![6y+4y+6-4=y+7\\10y+2=y+7](https://tex.z-dn.net/?f=6y%2B4y%2B6-4%3Dy%2B7%5C%5C10y%2B2%3Dy%2B7)
Simplifying to find value of y:
![10y-y=7-2\\9y=5\\y=\frac{5}{9}](https://tex.z-dn.net/?f=10y-y%3D7-2%5C%5C9y%3D5%5C%5Cy%3D%5Cfrac%7B5%7D%7B9%7D)
So, after solving the expression
the value of y is ![y=\frac{5}{9}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B5%7D%7B9%7D)
Keywords: Solving Fractions
Learn more about Solving Fractions at:
#learnwithBrainly
Answer:
what are we to find exactly bcoz I can't see anything question being ask here
35/4÷7/2=
35/4*2/7=70/28=
35/14 meters or 2 7/14 meters as a mixed number.
Answer:
The smallest number of chocolates in the box is 124.
Step-by-step explanation:
There are always 4 bars of chocolates left in the box when they are share equally among 8, 10, or 12 children.
This means that the smallest number of chocolates in the box is 4 added to the least common multiple of 8, 10 and 12.
LCM(8,10,12).
We factore them by prime factors until all are 1. So
8 - 10 - 12|2
4 - 5 - 6|2
2 - 5 - 3|2
1 - 5 - 3|3
1 - 5 - 1|5
1 - 1 - 1
So
lcm(8,10,12) = 2*2*2*3*5 = 8*15 = 120
Adding 4: 120 + 4 = 124
The smallest number of chocolates in the box is 124.