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Bingel [31]
4 years ago
14

What is logarithmic form of 81^1/2=9

Mathematics
1 answer:
aleksandrvk [35]4 years ago
5 0
Log81 (9) = 1/2
The 81 is a subscript don’t know if I could type it like that so I just put it like that
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Javier asks his mother how old a tree in their yard is. His mother says, "The sum of 10 and two-thirds of that tree's age, in ye
Sloan [31]

Answer:

His error is adding 10 and 2/3 before multiplying by a(age of the tree)

Step-by-step explanation:

The sum of 10 and two-thirds of that tree's age, in years, is equal to 50.

Correct equation

Sum = addition (+)

two-thirds = 2/3

The tree's age = a

10 + 2/3a = 50

2/3a = 50 - 10

2/3a = 40

a = 40 ÷ 2/3

= 40 × 3/2

= 60

a = 60 years

Javier writes the equation

(10 + two-thirds) a = 50

(10 + 2/3)a = 50

(30+2/3)a = 50

32/3a = 50

a = 50 ÷ 32/3

= 50 × 3/32

= 150/32

a = 150/32

His error is adding 10 and 2/3 before multiplying by a(age of the tree)

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3 years ago
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8 0
3 years ago
Write an absolute value equation that has the solutions 2 = 8 and x = 18.
Alex777 [14]

Answer:

Absolute value equation: |x - 13| = 5

Step-by-step explanation:

The midpoint between 8 and 18 is;

(8 + 18)/2 = 26/2 = 13

This means that the distance between 13 and either 8 or 18 will be 5.

Now, the absolute value equation will have to say that the distance between x and 13 is 5.

Thus, plugging those numbers into the pattern of |x - m| = b. Where m is the midpoint and b is the distance from midpoint to either values of x.

This gives us the absolute value equation: |x - 13| = 5

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iragen [17]

Answer: A false, B true, C true

Step-by-step explanation:

A) intercept with y axis

That means x=0

y= 3*0-2

y= -2 So A is false

B) intercept with x axis

That means y=0

0= 3x-2

2=3x

2/3= x B is true

C) The form of linear function is

f(x)= mx +n, where m is the slope

In this case m= 3 so C is true

8 0
3 years ago
Convert 150 minutes into days.<br><br> i need to bring my grade up so can you guys pls help me.
maxonik [38]

Answer:

0.1 days

Step-by-step explanation:

If you need an explanation just ask

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