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ad-work [718]
2 years ago
7

There are 3 types of bills, 4 quarters, and 5 dimes in Mrs. Short's wallet. The contains twice as many 1 bills as 5 dallor bills

. The number of 20 dallors multiplied by 2 is 7 more than the total number of 1 dallor and 5 dallor combined. How mnay of each type of bill is in Mrs. Short's wallet if it contains a total of 182.50 dallors
Mathematics
2 answers:
kondaur [170]2 years ago
7 0

Answer:

There are 3 types of bills, 4 quarters, and 5 dimes in Mrs. Short's wallet. The contains twice as many 1 bills as 5 dallor bills. The number of 20 dallors multiplied by 2 is 7 more than the total number of 1 dallor and 5 dallor combined. How mnay of each type of bill is in Mrs. Short's wallet if it contains a total of 182.50 dallors

Step-by-step explanation:

.

Agata [3.3K]2 years ago
4 0

Step-by-step explanation:

$182.50-$1.50=$181.00. Answer??

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Inversely proportional
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The ratio of dogs to cats at an animal shelter is 33 to 22. How many dogs are at the shelter if there is a total of 3030 animals
Elena-2011 [213]
D : c = 33 : 22
where d is the number of dogs and c is the number of cats;
and: d + c = 3030
33 c = 22 d  / : 11
3 c = 2 d
From the other equation: c = 3030 - d
3 * ( 3030 - d ) = 2 d
9090 - 3 d = 2 d
5 d = 9090
d = 9090 : 5
d = 1818
Answer: There are 1818 dogs in the shelter.
 
4 0
3 years ago
PLEASE HELP ASAP. I HAVE A VERY IMPORTANT TEST AND I NEED HELP
Katarina [22]

Answer:

i think 4 is b

Step-by-step explanation:

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3 years ago
A multinational firm wants to estimate the average number of hours in a month that theiremployees spend on social media while on
elena55 [62]

Answer:

95% of the population spent between 16.8 hours to 26.2 hours on social media per month

Step-by-step explanation:

  1. subtracting 1 from sample size: 83-1= 82
  2. Note Mean=21.5 and standard deviation=2.5
  3. Subtracting confidence interval from 1 and dividing by 2: (1-0.95)/2=0.025
  4. At α=0.025 and dF=82,  the t-distribution table gives  1.984
  5. Divide standard deviation by square root of sample size: 21.5/√83= 2.36
  6. Multiplying answer in step 4 by answer in step 5: 2.36×1.984= 4.68
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7 0
3 years ago
Read 2 more answers
A professor grades students on four tests, a term paper, and a final examination. Each test counts as 15% of the course grade. T
alina1380 [7]

Answer:

The Alans's average for the course is 84.5

Step-by-step explanation:

We are given

There are 4 tests, A Term paper and a Final examination.

Score = 92, 78, 82, 90.

Term paper score = 80

Final examination score = 86

Weighted mean = ∑ w.f/∑w

     also the sum of all the weights is 100% = 1

weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1

                         = 51.3 + 33.2

                         =  84.5

Therefore the Alans's average for the course is 84.5

5 0
2 years ago
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