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ad-work [718]
2 years ago
7

There are 3 types of bills, 4 quarters, and 5 dimes in Mrs. Short's wallet. The contains twice as many 1 bills as 5 dallor bills

. The number of 20 dallors multiplied by 2 is 7 more than the total number of 1 dallor and 5 dallor combined. How mnay of each type of bill is in Mrs. Short's wallet if it contains a total of 182.50 dallors
Mathematics
2 answers:
kondaur [170]2 years ago
7 0

Answer:

There are 3 types of bills, 4 quarters, and 5 dimes in Mrs. Short's wallet. The contains twice as many 1 bills as 5 dallor bills. The number of 20 dallors multiplied by 2 is 7 more than the total number of 1 dallor and 5 dallor combined. How mnay of each type of bill is in Mrs. Short's wallet if it contains a total of 182.50 dallors

Step-by-step explanation:

.

Agata [3.3K]2 years ago
4 0

Step-by-step explanation:

$182.50-$1.50=$181.00. Answer??

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ANSWER

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

EXPLANATION

From the Pascal's triangle,

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Because of the negative sign, the expansion will alternate sign.

(x - y) ^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}

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