All categories

3 years ago

Help I don’t understand number 18 I wrote the equation but I need help solving it the equation is 13 n - 1.50= 35.50

Mathematics

1 answer:

lozanna [386]3 years ago

5 0

Hi there!

It appears you've written the equation wrong.

It should be: 13 + 1.5n ≤ 35.5

(13 - 13) + 1.5n ≤ (35.5 - 13)

1.5n ≤ 22.5

1.5n / 1.5 ≤ 22.5 / 1.5

n ≤ 15 rides

The most amount of rides you can take is 15.

Hope this helps.

You might be interested in

Answer for brainlist and extra points ☀️

tia_tia [17]

Answer:x+2y-12=0

Step-by-step explanation:

3x+6y=36

-36. -36

3x+6y-36=0

Divide by 3 to get

X+2x-12=0

8 0

2 years ago

Solve -24 = 6x explain how to solve for x

stiv31 [10]

you would divide both sides by 6 to get your answer. i hope this helps :)

6 0

2 years ago

Read 2 more answers

Someone help I don’t understand

Rina8888 [55]

Answer:

a)C

b)E

Step-by-step explanation:

a) You have to pick a vowel. There are three vowels and a total of 6 letters so it is 3/6 so the answer is C

b) Picking a card that is not T. None of the 6 letters are T so the probablity of picking a card with no T is 1. So the answer is E.

4 0

2 years ago

Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20

Mice21 [21]

Power and chain rule (where the power rule kicks in because $\sqrt x=x^{1/2}$ ):

$\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'$

Simplify the leading term as

$\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}$

Quotient rule:

$\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}$

Chain rule:

$(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)$

$(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)$

Put everything together and simplify:

$\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}$

$=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}$

$=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}$

5 0

3 years ago

Abcd is a parallelogram. Photo provided

Savatey [412]

The correct answer is A. 120 ft squared because you must multiply the height times the width which comes to 120.

8 0

2 years ago