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Alika [10]
3 years ago
14

What quadrent is (-2,7) in

Mathematics
2 answers:
Verizon [17]3 years ago
8 0
Quadrant two.

Due to the fact that the negative 2 would bring it to the left side and the 7 brings it up so itll be on upper left corner or quadrant 2
lawyer [7]3 years ago
7 0
Quadrant 2.

This is because the x-value is negative, and therefore is on the left side of the axis; and the y-value is positive, and therefore is on the top side of the axis. Putting this together, we find that (-2.7) is in Quadrant 2. 
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I’ll rate your answer 5 stars if you can help me pls
kap26 [50]
Answer:
104:2=52
3*52=156
1) 156/3
2)364/7
7*52=364
7 0
2 years ago
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What addition doubles facts can help you find 4+3
Oduvanchick [21]
3+3= 6

6+1= 7 is your answer

3 0
3 years ago
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What is the radius of a circle with circumference 56 inches
pochemuha

Answer:

The answer is 8.91 or 8.9

Step-by-step explanation:

SInce the circumference is 56, you'll divide it by pi or 3.14. It's as if you're doing it backwards, but not always. After you divide it by 3.14, you'll get your diameter, or in this case, 17.8. Divide the diameter by 2 because the diameter is twice the radius. Eventually your final answer will be 8.91 or 8.9

5 0
2 years ago
I need help with this so can someone please help me
slava [35]

9514 1404 393

Answer:

  • 16x
  • -4x +4
  • 8x +8
  • 8x

Step-by-step explanation:

Like terms are ones with the same variable (or set of variables). Here, any x-terms are "like" terms. They are combined by adding their coefficients.

  4x +4x +4x +4x = x(4+4+4+4) = 16x

  -7x +4 +3x = x(-7+3) +4 = -4x +4

  3x +5x +8 = x(3+5) +8 = 8x +8

  4x +4x = x(4+4) = 8x

3 0
3 years ago
Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)
Lisa [10]

Answer:

f(x) = 4x^2 - 3x + 6

Step-by-step explanation:

Quadratic function is given as f(x) = ax^2 + bx + c

Let's find a, b and c:

Substituting (0, 6):

6 = a(0)^2 + b(0) + c

6 = 0 + 0 + c

c = 6

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

f(x) = ax^2 + bx + c

16 = a(2)^2 + b(2) + 6

16 = 4a + 2b + 6

16 - 6 = 4a + 2b + 6 - 6

10 = 4a + 2b

10 = 2(2a + b)

\frac{10}{2} = \frac{2(2a + b)}{2}

5 = 2a + b

2a + b = 5 => (Equation 1)

Substituting (3, 33), and c = 6

f(x) = ax^2 + bx + x

33 = a(3)^2 + b(3) + 6

33 = 9a + 3b + 6

33 - 6 = 9a + 3b + 6 - 6

27 = 9a + 3b

27 = 3(3a + b)

\frac{27}{3} = \frac{3(3a + b)}{3}

9 = 3a + b

3a + b = 9 => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

3a + b = 9

2a + b = 5

a = 4

Replace a with 4 in equation 2.

2a + b = 5

2(4) + b = 5

8 + b = 5

8 + b - 8 = 5 - 8

b = -3

The quadratic function that represents the given 3 points would be as follows:

f(x) = ax^2 + bx + c

f(x) = (4)x^2 + (-3)x + 6

f(x) = 4x^2 - 3x + 6

6 0
3 years ago
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