A) All triangles add up to 180° so when given two angles, add those up and subtract them from 180° . That will give you the missing angle.
3-5) When you do A above, and receive the measurement of angle 1, it will also equal 2 and you can repeat A for missing angle 3
6-8) Find the missing angle next to 1, and then subtract that from 180°. That number is the answer for 1. 2 is 55 as its a complimentary (i think thats the right term) angle. Which means it is on the opposite side of an angle. I don't remember how to find 3 however, its been a few years since I've done triangles.
2x -20 -1 =0
2x -21=0
2x=21
x= 10.5
Step-by-step explanation:
<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
Let distance travelled by Nichol =x
<h2>ATQ</h2>
Nichol runs 1.6miles .
If you are needing to find the distance between the two points, you must use a simple formula, cleverly named, the distance formula. Since I can't input special characters into the answer box, I'll explain it the best I can.
( The square root of ( (x - x)^2 + (y - y)^2 ) )
First, we need to find the first x subtracted from the second x, as so:
(4,5) and (7,-9)
4 - 7 = -3
Now, we square the -3.
-3^2 =
-3 * -3 = 9
Next, we have to find the first y subtracted from the second y.
(4,5) and (7,-9)
5 - (-9) = 14
Now, we square the 14.
14^2 =
14 * 14 = 196
Let's see how the numbers fit in the formula:
sqrt((x - x)^2 + (y - y)^2)
sqrt((4 - 7)^2 + (7 - (-9))^2)
sqrt((-3)^2 + (14)^2)
sqrt( 9 + 196 )
This is where we currently are in the formula, all we have to do now is square root the total of 9 + 196.
sqrt( 9 + 196 )
sqrt( 205 )
The square root of 205 = 14.31782106...
There are a few answers you can consider:
1) sqrt(205)
2) 14.32 units
or
3) 14.31782106
Depending on the answer you desire, use the one that sounds the most correct to you. Although all three are correct, it may not be the answer you require.
Hope I could help! If my math is incorrect, or I provided answers you were not looking for, please let know! However, if my answer is correct and well explained, please consider marking my answer as <em>Brainliest</em>! :)
Have a good one.
God bless!
