Question

Which reaction below represents the second ionization of sr?

Answer 1

e.sr⁺(g) → sr2⁺(g) + e⁻
When remove first electron became Sr⁺, second Sr²⁺.

Answer 2

Answer:

$Sr^{+} (g)-->Sr^{2+} (g)+e$

Explanation:

Ionization is removal of most loosely bound electron from an isolated gaseous atom.

First ionization is the removal from a neutral atom.

The equation for it is

a) $Sr(g)-->Sr^{+} (g)+e$

Second ionization is the removal from a monopositive ion of the atom.

The equation is:

$Sr^{+} (g)-->Sr^{2+} (g)+e$

In ionization there is no addition of electron thus all other equations are cannot be correct.