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telo118 [61]
3 years ago
8

Sam prepares a solution of sodium chloride with a concentration of 8 g/dm³. If he only used 2g of sodium chloride, what volume o

f water did he dissolve it in, in cm³?
Chemistry
1 answer:
adoni [48]3 years ago
4 0

The volume of water he dissolved the solute is 250 cubic centimeter.

<u>Explanation</u>:

            Concentration = mass of solute in g / volume in dm^3

The concentration of a solution is defined as the ratio of mass of solute in grams to the volume of water in dm^3.

If concentration of a solution = 8 g/dm^3.

mass of solute =2 g.

Volume of a water = 2 / 8 = 0.25 dm^3. (or) 250 cubic centimeter.

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What will create a insoluble salt with a potassium ion
navik [9.2K]

Explanation:

1) The dissolution of the salt potassium sulfite:

K₂SO₃(aq) → 2K⁺(aq) + SO₃²⁻(aq).

Potassium has +1 charge because it lost one electron to accomplish stabile electron configuration of noble gas argon.

2) From dissolution reaction: n(K⁺) : n(SO₃²⁻) = 2 : 1.

n(K⁺) = 0.700 mol.

0.700 mol : n(SO₃²⁻) = 2 : 1.

n(SO₃²⁻) = 0.700 mol ÷ 2.

n(SO₃²⁻) = 0.350 mol; amount of sulfite anions.

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3 years ago
Give three examples of energy traveling in waves
mrs_skeptik [129]

Answer:

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Explanation:

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3 years ago
Describe one example of an energy transformation in this diagram and explain why it is a transformation. Repeat this description
iren [92.7K]

Answer:

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Explanation:

here u go :P

8 0
3 years ago
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Ionic compound of potassium fluoride.​
LiRa [457]

Answer:

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Explanation:

8 0
4 years ago
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g 32.53 g of a solid is heated to 100.oC and added to 50.0 g of water in a coffee cup calorimeter and the contents are allowed t
Radda [10]

Answer:

0.886 J/g.°C

Explanation:

Step 1: Calculate the heat absorbed by the water

We will use the following expression

Q = c × m × ΔT

where,

  • Q: heat
  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

Q(water) = c(water) × m(water) × ΔT(water)

Q(water) = 4.184 J/g.°C × 50.0 g × (34.4 °C - 25.36 °C) = 1.89 × 10³ J

According to the law of conservation of energy, the sum of the energy lost by the solid and the energy absorbed by the water is zero.

Q(water) + Q(solid) = 0

Q(solid) = -Q(water) =  -1.89 × 10³ J

Step 2: Calculate the specific heat capacity of the solid

We will use the following expression.

Q(solid) = c(solid) × m(solid) × ΔT(solid)

c(solid) = Q(solid) / m(solid) × ΔT(solid)

c(solid) = (-1.89 × 10³ J) / 32.53 g × (34.4 °C - 100. °C) = 0.886 J/g.°C

8 0
3 years ago
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