A phylogenetic tree may be built using morphological (body shape), biochemical, behavioral, or molecular features of species or other groups. In building a tree, we organize species into nested groups based on shared derived traits (traits different from those of the group's ancestor).
If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first
<h3>What is EDTA ?</h3>
EDTA is a type of chemical which binds certain metal ions such as calcium and magnesium. some of the functions of EDTA includes:
- Preventing blood clotting of blood samples
- prevention of the formation of Biofilm by bacterias
The EDTA will readily react with metals which have a hiogher number of free ions that it can bind with.
Hence we can conclude that If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first.
Learn more about EDTA : brainly.com/question/10818175
Answer: There are 0.006 moles of acid in the flask.
Explanation:
Given: 
= 21.35 mL, 
= 0.150 M
= 25.0 mL, 
= ?
Formula used to calculate molarity of 
is as follows.
Substitute the values into above formula as follows.
As molarity is the number of moles of a substance present in a liter of solution.
Total volume of solution = 
= 21.35 mL + 25.0 mL
= 46.36 mL (1 mL = 0.001 L)
= 0.04636 L
Therefore, moles of acid required are calculated as follows.
Thus, we can conclude that there are 0.006 moles of acid in the flask.
The charge of Br changed from –1 to 0, therefore it is the
element which is oxidized. Since it is oxidized then Br is also the reducing
agent.
The charge of Mn changed from +4 to +2 therefore it is the
element which is reduced. Since Mn is reduced, then MnO2 is the oxidizing
agent.
The half –reactions are:
Br: 2Br --> Br2 + 2e-
Mn: MnO2 --> Mn2+
First balance oxygen by adding H2O:
MnO2 --> Mn2+ + 2H2O
Then balance hydrogen by adding H+ ions:
4H+ + MnO2 --> Mn2 + 2H2O
Then the appropriate electrons:
4e- + 4H+ + MnO2 --> Mn2 + 2H2O
Multiply the half-reaction of Br by 2 because the half-reaction
of Mn has 4 electrons.
4Br --> 2Br2 + 4e-
Combine the two half reactions and cancel common factors:
4Br- + 4H+ + MnO2 --> 2Br2 + Mn2 + 2H2O
