Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
<u>Step-by-step explanation:</u>
As given by the statement in the problem,
Q may be the middle point, which cut the diagonal PA into 2 equal halves.
In rhombus, diagonals meet at right angles.
which means that PQ = QA
x+2 = 3x - 14
Grouping the terms, we will get,
3x -x = 14+ 2
2x = 16
dividing by 2 on both sides, we will get,
x = 16/2 = 8
8+2 = 3(8) - 14 = 10 = PQ or QA
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>
Answer: (9, 10800)
Step-by-step explanation:
We will first let x be the number of years and y be the total cost.
In that case, let's plug in the values for each into the equation <em>y=mx+b, </em>where m is the slope and b is the y-intercept.
The y-intercept will be the <u>value we start with before any years pass</u>, so it will be the <u>installation cost</u>. The slope is <u>how fast the total cost will increase</u>. Since the <u>operation costs</u> have to be added on every year, it will be our slope.
With that in mind, let's create both of our equations:
- y = 900x + 2700 (Oil system)
- y = 200x + 9000 (Solar system)
Since y is solved for in the first equation, we can substitute it into the second equation:
<em>[Subtracting 200x from both sides]</em>
<em />
<em>[Subtracting 2700 from both sides]</em>
<em />
<em>[Dividing both sides by 700]</em>
<em />
We can now substitute 9 for x in any equation and solve for y. Here I substituted it into the first one:
<em>[Multiplying]</em>
<em />
<em>[Adding]</em>
Hence, the solution to this linear system is (9, 10800).
What is the object (Circle) or what
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