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Viefleur [7K]
4 years ago
9

A 2.1-kg brick is placed gently upon a 2.9-kg cart originally moving with a speed of 26 cm/s. determine the post-collision speed

of the combination of brick and cart.
Physics
1 answer:
vagabundo [1.1K]4 years ago
6 0
By conservation of linear amount of movement, we have to
 p1 = p2
 Where, p = m * v.
 So, using the definition for this case, we have:
 (2.9 kg)•(26 cm/s) = (2.1 kg + 2.9 kg)•v 
 75.4 kg•cm/s = (5.0 kg)•v 
 v = 15.1 cm/s
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Answer:

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Explanation:

Given that,

Mass of the block A, m_A=4.03\ kg

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Mass of the block B, m_B=4.8\ kg

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Let p is the total momentum of the system before the collision. It is given by :

p=m_Av_A+m_Bv_B\\\\p=4.03\times 3+4.84\times (-3.6)\\\\p=-5.334\ kg-m/s

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3 years ago
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3 years ago
To reduce inductive reactance, what devices are normally placed on transmission or distribution lines?
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3 years ago
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Answer:

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butalik [34]

Answer:

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(self-explanatory)

I hope this helps, have a nice day.

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