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Art [367]
3 years ago
8

A certain engine extracts 1300 J of heat from a hot temperature reservoir and discharges 700 J of heat to a cold temperature res

ervoir. What is the efficiency of this engine?
Physics
1 answer:
patriot [66]3 years ago
3 0

Answer:

the efficiency of the heat engine is 46%

Explanation:

As we know that the heat extracted from engine is 1300 J

also we know that the heat discharged to the reservoir is 700 J

So we will find efficiency as

\eta = 1 - \frac{Q_2}{Q_1}

\eta = 1 - \frac{700}{1300}

so we have

\eta = 0.46

the efficiency of the heat engine is 46%

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Answer:

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Explanation:

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3 years ago
Density of water is 1000 kg/m3 and that of glass is 2500 kg/m3 . The speed of light will be maximum in
dalvyx [7]
Water I believe sorry if wrong
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3 years ago
Please help !
BartSMP [9]

Answer:

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4 0
4 years ago
A carnival Ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute. What is the accelerat
Tanzania [10]

If a Ferris wheel has a 15-m radius and completes five turns about its horizontal axis every minute then the acceleration of a passenger at his lowest point during the ride is 4.11 \text{m/s}^{2}.

Calculation:

Step-1:

It is given that the radius of the Ferris wheel is r=15 m, and the angular speed of the wheel is \omega=5rev/min.

It is required to find the angular acceleration of a passenger at his lowest point during the ride.

The formula required to calculate the angular acceleration is, a=\omega ^2 r.

Step-2:

Now substituting the given values into the equation to get the value of the angular acceleration.

\begin{aligned}a &=\omega^{2} r \\&=(5 \mathrm{rev} / \mathrm{min})^{2}(15 \mathrm{~m}) \\&=\left(5 \mathrm{rev} / \mathrm{min} \times \frac{\left(\frac{2 \pi}{60}\right) \mathrm{rad} / \mathrm{sec}}{1 \mathrm{rev} / \mathrm{min}}\right)^{2}(15 \mathrm{~m}) \\&=(0.2741 \times 15) \mathrm{m} / \mathrm{s}^{2} \\&=4.11 \mathrm{~m} / \mathrm{s}^{2}\end{aligned}

The acceleration is towards upwards that means towards the center of the wheel.

Learn more about the angular acceleration:

brainly.com/question/1592013

#SPJ4

3 0
2 years ago
Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2.
IrinaVladis [17]

Answer:

option C

Explanation:

Let mass of the bullet be m and velocity be v

mass of gun be M and bullet be V

now,

using conservation of momentum for gun 1

(M+m) V' = 2 mv + 3 MV

V' = 0

3 M V = - 2 mv

momentum of gun 1 =- 2 mv---------(1)

now for gun 2

(M+m) V' = mv + MV

V' = 0

M V = - mv

momentum of gun 1 = -mv-----------(2)

dividing equation (1) by (2)

\dfrac{P_m1}{P_m2} = \dfrac{- 2mv}{-mv}

\dfrac{P_m1}{P_m2} = \dfrac{2}{1}

the correct answer is option C

7 0
3 years ago
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