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3 years ago

What is the value of the following function when x = 0?

Mathematics

2 answers:

Irina-Kira [14]3 years ago

5 0

Answer:

y= -2

Step-by-step explanation:

LenaWriter [7]3 years ago

3 0

Answer:

y = negative 2

Step-by-step explanation:

we know that

The y-intercept is the value of the function (y) when the value of x is equal to zero

In this problem

The y-intercept is given by the point (0,-2)

Therefore

when the value of x=0

The value of the function is y=-2

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A truck can be rented from Company A for $70 a day plus $0.20 per mile. Company B charges $20 a day plus $0.40 per mile to r

Otrada [13]

Answer:

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

Step-by-step explanation:

Given that:

Rent per day of company A = $70

Per mile charges = $0.20

Let,

x be the number of miles.

A(x) = 0.20x + 70

Rent per day of company B = $20

Per mile charges = $0.40

B(x) = 0.40x + 20

For make Company A better deal,

A(x) > B(x)

0.20x+70 > 0.40+20

0.20x-0.40x>20-70

-0.20x>-50

Dividing both sides by -0.20

$\frac{-0.20x}{-0.20}>\frac{-50}{-0.20}\\x>250$

Hence,

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

8 0

3 years ago

On a 16 scale drawing of a bike, one part is 3 inches long. How long will the actual bike part be?

Oksanka [162]

Multiply 16*3 to get 48, the bike is 48 units so 16:1,16/1=16. So the answer would be 16. Hope I helped!

4 0

3 years ago

Read 2 more answers

Use these functions to answer the questions.

Elenna [48]

Part A
We have $f\left(x\right)=\left(x+3\right)^2-1$ . To solve for the x-intercept, we set f(x) equal to 0. That is
$\left(x+3\right)^2-1=0$

$\left(x+3\right)^2=1$

Take the square root of both sides,
$x+3=1$

$x=-2$

The x-intercept is (-2,0).

To solve for the y-intercept, we set x=0. That is
$y=\left(0+3\right)^2-1=3^2-1=9-1=8$

The y-intercept is (0, 8)

The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is (-3, -1).

Part B.
We have $g\left(x\right)=-2x^2+8x+3$ .
Factor out -2
$=-2\left(x^2-4x\right)+3$

Complete the square
$=-2\left(x^2-4x+4\right)+3-2\left(4\right)$

Simplify
$g(x)=-2\left(x-2\right)^2-5$

Part C
We have $h\left(t\right)=-16t^2+28t$ .
The maximum height is 12.25 feet after 0.875 seconds from the time of the jump. The dolphin will be back in the water after 1.75 seconds. The graph of the jump is shown in the photo.