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sergey [27]
3 years ago
6

What is the value of the following function when x = 0?

Mathematics
2 answers:
Irina-Kira [14]3 years ago
5 0

Answer:

y= -2

Step-by-step explanation:

LenaWriter [7]3 years ago
3 0

Answer:

y = negative 2

Step-by-step explanation:

we know that

The y-intercept is the value of the function (y) when the value of x is equal to zero

In this problem

The y-intercept is given by the point (0,-2)

Therefore

when the value of x=0

The value of the function is y=-2

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Find all the zeroes of the equation. x4 – 6x2 – 7x – 6 = 0
NeX [460]

Answer:

-2, 3,  -0.5 + 0.866i,   -0.5 - 0.866i.

Step-by-step explanation:

As the last term is -6 , +/- 2 , +/- 3 are possible zeroes.

Try 2:-

(2)^4 - 6(2)^2 - 7(2) - 6 = -28 so  2 is not a zero.

3:-

(3)^4 - 6(3)^2 - 7(3) - 6 = 0 so 3 is a zero.

(-2)^4 - 6(-2)^2 - 7(-2) - 6 =  0 so -2 is also a zero.

Divide the function by (x +2)(x - 3),  that is  x^2 - x - 6

gives  x^2 + x + 1

x^2 + x + 1

So we have x^2 + x + 1 = 0

x =  [-1 +/- √(1^1 - 4*1*1)] / 2

= -1 + √(-3) / 2 , - 1 - √(-3)  / 2.

= -0.5 + 0.866i, -0.5 - 0.866i

7 0
3 years ago
Help help help help (-_-)
g100num [7]

Answer:

98

Step-by-step explanation:

4 0
3 years ago
In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each
Rudiy27

Answer:

N(t) = 972(1.015)^{t}

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

N(t) = N(0)(1+r)^{t}

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that N(0) = 972

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that r = 0.015

Then

N(t) = N(0)(1+r)^{t}

N(t) = 972(1+0.015)^{t}

N(t) = 972(1.015)^{t}

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

N(t) = 972(1.015)^{t}

N(12) = 972(1.015)^{12}

N(12) = 1162

The number of students enrolled in 2014 is 1162.

7 0
3 years ago
Boyle’s law states that the volume of a gas varies inversely with applied pressure. Suppose the pressure on 60 cubic meters of g
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8 0
3 years ago
Read 2 more answers
Pls I need help with his math problem
Leno4ka [110]

Answer:

  a) P = 0.08s +200

  b) $488

  c) $6250

Step-by-step explanation:

<h3>a)</h3>

Your answer is correct. The commission rate is multiplied by the sales amount, and that product is added to the guaranteed pay to get the paycheck amount:

  P = 0.08s +200

__

<h3>b)</h3>

Fill in 3600 for s and do the arithmetic.

  P = 0.08×3600 +200 = 288 +200 = 488

The paycheck amount will be $488.

__

<h3>c)</h3>

Use the equation for part (a) and solve for P = 700.

  700 = 0.08s +200

  500 = 0.08s . . . . . . subtract 200

  500/0.08 = s = 6250 . . . dollars; divide by the coefficient of s to get this

Sales would have to be $6250.

8 0
3 years ago
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