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Oksana_A [137]
3 years ago
13

A rectangle has a perimeter of 84 meters and a length of 35 meters. What is the width of the rectangle?

Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0
To find the perimeter of a rectangle, we can use this formula: 2L + 2W
Where L is the length and W is the width.

We know the perimeter and we know the length and we want to find the width.
Substitute the values back into the formula.

2(35) + 2W = 84
70 + 2W = 84
2W = 14 <-- Subtract both sides by 70
W = 7 <-- Divide both sides by 2

So, width is 7 meters long.

Afina-wow [57]3 years ago
8 0
84 - (35*2)
84 - 70
14 / 2
The width of the rectangle is 7.
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Answer:

A) 0.265

B) 0.0265

C) 0.837

D) 0.0837

E) 0.00265

F) 0.00837

Step-by-step explanation:

We are given;

√7 = 2.65 and √70 = 8.37

A) √0.07 can be rewritten as;

√(7 × 1/100)

Let's deal with the digits in the bracket.

Square root of 100 is 10. Thus;

√(7 × 1/100) = (1/10)√7 = (1/10) × 2.65 = 0.265

B) √0.0007

Rewrite to get;

√(7 × 1/10000)

Square root of 1/10000 is 1/100

Thus;

√(7 × 1/10000) = (1/100)√7 = (1/100) × 2.65 = 0.0265

C) √0.7

Like above;

√0.7 = √(70 × (1/100))

>> (1/10)√70 = (1/10) × 8.37 = 0.837

D) √0.007

Like above;

Rewrite to get;

√(70 × 1/10000)

Square root of 1/10000 is 1/100

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√(70 × 1/10000) = (1/100)√70 = (1/100) × 8.37 = 0.0837

E) √0.000007

Rewritten to;

√(7 × (1/1000000))

√(1/1000000) = 1/1000

Thus; √(7 × (1/1000000)) = 1/1000 × √7 = 1/1000 × 2.65 = 0.00265

F)√0.00007

Rewritten to;

√(70 × (1/1000000))

√(1/1000000) = 1/1000

Thus; √(70 × (1/1000000)) = 1/1000 × √70 = 1/1000 × 8.37 = 0.00837

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