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Llana [10]
3 years ago
8

NEED HELP PLEASE ANSWER

Mathematics
2 answers:
Mariana [72]3 years ago
5 0
1430 miles he was right
ANEK [815]3 years ago
4 0

Answer:

I think its 1430 miles

Step-by-step explanation:

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Derek spends $3 on breakfast and $5.50 on lunch every school day how much does he spend in a week
goldfiish [28.3K]
      Work:
$3 x 7 = $21
$5.50  x  7 = $38.50
$38.50 + $21= $59.50

Derek spend $59.50 in a week.
8 0
3 years ago
Read 2 more answers
Everytime Evan walks his neighbors. He gets $8 and he has four or five times and there's a video game
Mariulka [41]
So what’s the question
8 0
3 years ago
I need help please pleaseeeeee
Yuliya22 [10]

Answer:

19.64 ft

Step-by-step explanation:

7/25 = 5.5/x

7x = 137.5

x = 19.64

3 0
3 years ago
walking at a constant speed, a person walks 4/7 of a mile in 18 minutes. how far will he walk in 30 minutes?
zhenek [66]
First of all you find out how much they go in 18 minutes:
1 minute = (4/7)/18
Times this by 30, to get how far he gets in 30 minutes.

((4/7) / 18)*30 = <span>0.952 (3 DP)
In 30 minutes the person walks 0.952 (3DP) of a mile


</span>
7 0
3 years ago
An airliner carries 150 passengers and has doors with a height of 78 in. Heights of men are normally distributed with a mean of
iogann1982 [59]

Answer:

Step-by-step explanation:

x, height of men is N(69, 2.8)

Sample size n =150

Hence sample std dev = \frac{2.8}{\sqrt{150} } =0.229

Hence Z score = \frac{x-69}{0.229}

A) Prob that a random man from 150  can fit without bending

= P(X<78) = P(Z<3.214)=1.0000

B) n =75

Sample std dev = \frac{2.8}{\sqrt{75} } =0.3233

P(X bar <72) = P(Z<9.28) = 1.00

C) Prob of B is more relevent because average male passengers  would be more relevant than a single person

(D) The probability from part (b) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height.

3 0
3 years ago
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